Use distributive property: a(b + c) = ab + ac.
2(w + 7) + 6(3w - 1) = (2)(w) + (2)(7) + (6)(3w) + (6)(-1)
= 2w + 14 + 18w - 6
<em>combine like terms</em>
= (2w + 18w) + (14 - 6) = 20w + 8
<h3>Answer: 2(w + 7) + 6(3w - 1) = 20w + 8</h3>
Answer:
11.42 boxes
Step-by-step explanation:
For the first box bought, there is a 100% chance of getting a unique toy (since you still don't have any). E₁ = 1.
After that, there is a 4 in 5 chance of getting a unique toy from the next box, the expected number of boxes required is:

For the next unique toy, there is now a 3 in 5 chance of getting it:

Following that logic, there is a 2 in 5 chance of getting the 4th unique toy:

Finally, there is a 1 in 5 chance to get the last unique toy:

The expected number of boxes to obtain a full set is:

Answer:
20.922
Step-by-step explanation:
Evaluate ln 7.2 on a calculator; the correct result is 1.974.
Multiply that by 3, obtaining 5.922.
Finally, add 15 to that result: y = 15 + 3 In 7.2 = 20.922
Answer:
5(2x-3)
Step-by-step explanation:
Answer:
229?
Step-by-step explanation: