Answer:
88
Step-by-step explanation:
Answer: triangle 1, triangle 2, and triangle 3
Step-by-step explanation:
Triangles 1 and 3 are congruent by SAS. So, by CPCTC, all three sides are congruent, making triangle 2 congruent to them as well by SSS.
3x + 1 = y
2x + 3y = 14
To solve this system of equations, we are going to use the substitution method. Substitution the equation where the variable is isolated into the second equation. In this system of equations, y is isolated, so we will replace y in the second equation with 3x + 1.
2x + 3y = 14
2x + 3(3x + 1) = 14
2x + 9x + 3 = 14
We will add the like terms and subtract 3 from both sides of the equation.
11x + 3 = 14
11x = 11
x = 1
In this system of equations, x is equal to 1. Now we will go back and solve for y, plugging in 1 for x.
3(1) + 1 = y
2(1) + 3y = 14
3 + 1 = y
2 + 3y = 14
4 = y
3y = 2
4 = y
4 = y
The solution to this system of equations is (1, 4).
Answer:
Mark C.
Step-by-step explanation:
If there are 27 students in both classes, it's logicial to multiply both classes by two to get the total students.
Since the <em>S</em> stands for the students absent, that should come after the brackets.
Here is a reference to the Inscribed Quadrilateral Conjecture it says that opposite angles of an inscribed quadrilateral are supplemental.
Explanation:
The conjecture, #angleA and angleC# allows us to write the following equation:
#angleA + angleC=180^@#
Substitute the equivalent expressions in terms of x:
#x+2+ x-2 = 180^@#
#2x = 180^@#
#x = 90^@#
From this we can compute the measures of all of the angles.
#angleA=92^@#
#angleB=100^@#
#angleC=88^@#
<span>#angleD= 80^@#</span>
