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pochemuha
3 years ago
9

Solve for x: 1/2x - 4 = 8

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0
First do 8 + 4 which is 12

Next do 12 times 2 which is 24

Final step is to do 24 divided by 1 which gets you 24

The answer is 24.
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Six nickels is what percent of one dollar? What percent of $2.00 would it be? Please help.
Deffense [45]
6\ nickels=6\times\ \$0.05=\$0.30\\\\\frac{0.03}{1}\cdot100\%=3\%\\\\6\ nickels\ is\ 3\%\ of\ \$1.\\\\\frac{0.03}{2}\cdot100\%=1.5\%\\\\6\ nickels\ is\ 1.5\%\ of\ \$2.
8 0
3 years ago
Solve by completing the square. x^2 + 4x – 1= 0
NNADVOKAT [17]

Answer:

x = -2 ± sqrt(5)

Step-by-step explanation:

x^2 + 4x – 1= 0

Add 1 to each side

x^2 + 4x – 1+1= 0+1

x^2 +4x = 1

Take the coefficient of x

4

Divide by 2

4/2 =2

Square it

2^2=4

Add it to each side

x^2 +4x+4=1+4

(x+2)^2 = 5

Take the square root of each side

sqrt((x+2)^2 )=± sqrt(5)

x+2 = ± sqrt(5)

Subtract 2 from each side

x+2-2 = -2 ± sqrt(5)

x = -2 ± sqrt(5)

8 0
3 years ago
How do I divide 178.8 by 24?
Doss [256]
<span>7.45 is the final answer

178.8/ 24 = about 7.45</span>
4 0
2 years ago
Prove that the value of the expression does not depend on a:<br><br> a−(6a−(5a−8))
djyliett [7]

Step-by-step explanation:

a−(6a−(5a−8))

a-(6a-5a+8)

a-6a+5a-8

6a-6a-8

0-8

=-8

so the answer doesn't depend on a

3 0
3 years ago
Need help as quickly as possible
Solnce55 [7]

The measure of the unknown angles in the kite are as follows;

  • x = 66 degrees
  • y = 158 degrees

<h3>How to find the measure of a kite?</h3>

A kite has two pairs of adjacent equal sides.

In other words, a kite is a quadrilateral that has 2 pairs of equal-length sides and these sides are adjacent to each other.

One pair of opposite angles is equal. Diagonals are perpendicular to each other.

A kite has four interior angles and the sum of these interior angles is 360°

Therefore, the measures of the

x = 66 degrees.

Let's find y.

y = 360 - 70 - 66 - 66

y = 158 degrees.

learn more on kites here: brainly.com/question/24263475

#SPJ1

6 0
1 year ago
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