Circumference of the circle = 2<span>πr
Here, r = 10 yards, so substitute it,
C = 2</span>π(10) = 20<span>π
In short, Your Answer would be Option C
Hope this helps!</span>
![p=1](https://tex.z-dn.net/?f=p%3D1)
To better understand the problem see the attached figure
we have
![\frac{2}{5}+p=\frac{4}{5}+\frac{3}{5}p](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%2Bp%3D%5Cfrac%7B4%7D%7B5%7D%2B%5Cfrac%7B3%7D%7B5%7Dp)
Multiply by
both sides
![5(\frac{2}{5}+p)=5(\frac{4}{5}+\frac{3}{5}p)](https://tex.z-dn.net/?f=5%28%5Cfrac%7B2%7D%7B5%7D%2Bp%29%3D5%28%5Cfrac%7B4%7D%7B5%7D%2B%5Cfrac%7B3%7D%7B5%7Dp%29)
![2+5p=4+3p](https://tex.z-dn.net/?f=2%2B5p%3D4%2B3p)
Group terms that contain the same variable p and move the constant to the other side of the equation
![5p-3p=4-2](https://tex.z-dn.net/?f=5p-3p%3D4-2)
![2p=2](https://tex.z-dn.net/?f=2p%3D2)
![p=1](https://tex.z-dn.net/?f=p%3D1)
Well
12h=8h-20
12h=20
-8h
4h=20
4divide by 20
it will =5
Answer:
there were 2 partners and 4 associates
Step-by-step explanation:
at 1300 per partner if you hire 2 thats 1300 x 2 = 2600
thrn 4 associates at 400 each 400 x 4 = 1600
now add 2600 + 1600 = 4200
The coordinates of the school is now (5,7).