Answer:from my understanding it should be D I would wait for someone else to answer just in case I’m wrong.
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
1/6
Step-by-step explanation:
1/3 + /1/6= 1/2
Because 1.5 is half of 3
Try to just put 10 or =10
Answer:
11 1/12
Step-by-step explanation:
6 1/3 = 19/3
7 1/4 = 29/4
2 1/2 = 5/2
19/3 + 29/4 - 5/2
We must find the LCM of 3, 4, and 2. This happens to be 12
3*4 = 12
4*3 = 12
2*6 = 12
Multiply each fraction by the factor that'll get it to 12.
19/3 * 4/4 = 76/12
29/4 * 3/3 = 87/12
5/2 * 6/6 = 30/12
Now go through the problem
76/12 + 87/12 - 30/12
76 + 87 = 163
163/12 - 30/12
163 - 30 = 133
133/12
Simplify
133/12 = 11.0833... or 11 1/12
Hope this helps.
