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3 years ago

3rd time posting this maybe this time ill get some help T^T

Mathematics

2 answers:

o-na [289]3 years ago

7 0

Answer:

(2,-7) (-7,7) (-7,-1) (2,-1) (-2,-7) (-7,-7) (-7,1) (-2,-1) (-2,7) (-7,-7) (7,-1) (-2,1)

Step-by-step explanation:

Step2247 [10]3 years ago

4 0

Answer:

(2,-7) (-7,7) (-7,-1) (2,-1) (-2,-7) (-7,-7) (-7,1) (-2,-1) (-2,7) (-7,-7) (7,-1) (-2,1)

WOW that took forever. I tried my best <3

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Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?

OlgaM077 [116]

Answer:

$a_n = 16(\frac{1}{4})^{n - 1}$

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = $\frac{1}{16}$

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = $ar^{n - 1}$ , where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

$\frac{1}{16} = a*\frac{1}{4}^{5 - 1}$

$\frac{1}{16} = a*\frac{1}{4}^{4}$

$\frac{1}{16} = a*\frac{1}{256}$

$\frac{1}{16} = \frac{a}{256}$

Cross multiply

$1*256 = a*16$

Divide both sides by 16

$\frac{256}{16} = \frac{16a}{16}$

$16 = a$

$a = 16$

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = $ar^{n - 1}$

nth term = $16*\frac{1}{4}^{n - 1}$

$a_n = 16(\frac{1}{4})^{n - 1}$

3 0

3 years ago

If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree) A) 32.5° B) 39.2° C) 50.5° D) 57.5°

Ilia_Sergeevich [38]

Answer:

D) 57.5°

Step-by-step explanation:

As the question is not complete. So, let's suppose it is a right angle triangle then, we can apply Pythagoras theorem to calculate the hypotenuse or the third side.

Pythagoras Theorem = $c^{2}$ = $a^{2} + b^{2}$

a = 7 and b = 11

$a^{2}$ = 49

$b^{2}$ = 121

Plugging in the values, we will get:

$c^{2}$ = 49 + 121

$c^{2}$ = 170

c = $\sqrt{170}$

To calculate the unknown angle B, we can use law of sine.

Law of sine = $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$

So,

$\frac{c}{sinC}$ = $\frac{b}{sinB}$

$\frac{\sqrt{170} }{sin90}$ = $\frac{11}{sinB}$

Sin90 = 1

sinB = $\frac{11}{\sqrt{170} }$

B = $sin^{-1}$ ( $\frac{11}{\sqrt{170} }$ )

B = 57.5°

8 0

3 years ago

At a strawberry stand Luisa paid $4.50 for 2 pounds of strawberries. How much would you expect to pay for five pounds or strawbe

Daniel [21]

Half of 4.50 is 2.25, so for one pound it would be $2.25.

To calculate five pounds, you need to add 2.25+2.25+2.25+2.25+2.25 = 11.25.

For five pounds of strawberry's, it would cost $11.25.

Hope this helped !

4 0

3 years ago

Read 2 more answers

A wheel rotated for 2 minutes. If it makes 3 & 2/7 rotations each minute, how many rotations does it make?

Kryger [21]

2 times 3 & 2/7 = 6 & 4/7

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3 years ago

Leroy owns a business earning $49,300 in profits. These profits are appreciating at about 2.9% each year. What are Leroy's profi

ladessa [460]

Answer:

$63,765.43

Step-by-step explanation:

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3 years ago