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ASHA 777 [7]
3 years ago
9

Solve for r to find the missing term in geometric sequence.

Mathematics
2 answers:
marusya05 [52]3 years ago
5 0

Answer:

20 18. on the answer is 18 and 20 give me the brainlyest

makkiz [27]3 years ago
3 0

Answer:

  • 8, 16, 32, 64, 128,...

Step-by-step explanation:

We observe the terms increase twice, therefore r = 2.

<u>The missing terms are:</u>

  • 32/2 = 16
  • 16/2 = 8

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What is the slope of the line that passes through the points (-4, 3) and (14, 0)?
Brut [27]

Answer:

1/6

Step-by-step explanation:

If you graph your points on a coordinate grid, you will see the rise/run. From the point -4, -3 to the point 14,0 ; there is a rise of 3 and a run of 18. The rise goes over the run and creates a fraction of 3/18 and 3/18 simplified is 1/6! Hope this helps!

6 0
2 years ago
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Solve 7n + 4 &lt; 9n – 3.
soldier1979 [14.2K]
I hope this helps you

6 0
3 years ago
Use the information to complete the task.
murzikaleks [220]

Answer:

14.25 - d

Step-by-step explanation:

8 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
How many defective telephones
zhenek [66]

Answer:

Option 3: 300 phones

Step-by-step explanation:

Given

Phone produces each day: 1000

Number of phones that were checked = 30

Defective phones = 9

So the probability of defective phones will be calculated by dividing the number of defective phones by total number of phones checked.

So, the probability of defective phones

= 9/30

= 0.3 or 30%

So, from 1000 phones the defective phones will be:

1000*0.3

= 300 Phones ..

5 0
3 years ago
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