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3 years ago

Solve for r to find the missing term in geometric sequence.

Mathematics

2 answers:

marusya05 [52]3 years ago

5 0

Answer:

20 18. on the answer is 18 and 20 give me the brainlyest

makkiz [27]3 years ago

3 0

Answer:

8, 16, 32, 64, 128,...

Step-by-step explanation:

We observe the terms increase twice, therefore r = 2.

<u>The missing terms are:</u>

32/2 = 16
16/2 = 8

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The quality-assurance program for a certain adhesive formulation process involves measuring how well the adhesive sticks a piece

Svetach [21]

Answer:

A) P ( X ≤ 160 ) = 0

B) Unusually small

C) process was no longer functioning correctly

D) P ( X ≥ 203 ) = 0.3821

E) Not unusually large

F) No-Evidence

G) P ( X ≤ 195 ) = 0.3085

H) Not unusually small

I) No evidence

Step-by-step explanation:

Given:-

- The random variable (X) denotes the adhesive strength is normally distributed with mean u = 200 N and standard deviation s.d = 10 N.

X ~ N ( 200 , 10^2 )

Solution:-

A) Find P(X ≤ 160), under the assumption that the process is functioning correctly.

- Determine the Z-score value:

Z-score = ( X - u ) / s.d

= ( 160 - 200 ) / 10

= -4

- Use the standardized z-table to determine the probability:

P ( X ≤ 160 ) = P ( Z ≤ -4 )

= 0

- Assuming the process is functioning properly then the adhesive strength of X = 160 N would be considered unusually small since the probability of occurrence is approximately 0.

- If we were to observe an adhesive strength process that gives us the value of 160 N can imply that the process is not functioning properly as its outside the 3 standard deviations from the mean value. ( Conclusive Evidence )

D) Find P(X ≥ 203), under the assumption that the process is functioning correctly.

- Determine the Z-score value:

Z-score = ( X - u ) / s.d

= ( 203 - 200 ) / 10

= 0.3

- Use the standardized z-table to determine the probability:

P ( X ≥ 203 ) = P ( Z ≥ 0.3 )

= 0.3821

- Assuming the process is functioning properly then the adhesive strength of X = 203 N would be not be considered unusually small since the probability of occurrence is in the heart of the bell curve.

- If we were to observe an adhesive strength process that gives us the value of 203 N can imply that the process is functioning properly as its within 1 standard deviation from the mean value. ( No evidence )

G) Find P(X ≤ 195), under the assumption that the process is functioning correctly.

- Determine the Z-score value:

Z-score = ( X - u ) / s.d

= ( 195 - 200 ) / 10

= -0.5

- Use the standardized z-table to determine the probability:

P ( X ≤ 195 ) = P ( Z ≤ -0.5 )

= 0.3085

- Assuming the process is functioning properly then the adhesive strength of X = 195 N would be not be considered unusually small since the probability of occurrence is in the heart of the bell curve.

- If we were to observe an adhesive strength process that gives us the value of 195 N can imply that the process is functioning properly as its within 1 standard deviation from the mean value. ( No evidence )

5 0

3 years ago

What is the product?

Sonja [21]

3/22 is the answer in simplest form

6 0

4 years ago

Read 2 more answers

Statistics: Hypothesis Testing

Lina20 [59]

Answer:

Yes, the mean age of onset of anorexia nervosa in women has decreased.

Step-by-step explanation:

When constructing confidence intervals, remember the acronym PANIC.

P (p definitions)

let p = the newly recorded mean age of the onset of anorexia nervosa in women

A (assumptions)

There is no evidence in the problem that the women were randomly or independently selected, but we will proceed as if they were. It is reasonable to assume that there are over 200 women in the world, so this sample is less than 10% of the total population. We will assume that the onset of anorexia nervosa has a fairly normal distribution, so the smaller sample size will suffice.

N (name the test)

Because the required conditions are met, we can construct a 95% confidence interval.

I (interval)

Interval = $\overline{x} \pm Z^{*} (\frac{\sigma}{\sqrt{n} })$

Interval = $14.250 \pm 1.96 (\frac{1.512}{\sqrt{20} })$

Interval = $14.250 \pm .6626$

Interval = (13.5874, 14.9126)

C (conclusion)

Based on this interval, I am 95% confident that the true mean age of the onset of anorexia nervosa in women is between 13.58 and 14.91 years. Since 15 is not included in this interval, I believe that the mean age of the onset of anorexia nervosa in women has decreased.

3 0

4 years ago

Read 2 more answers

Consider the equation below. Log Subscript 4 Baseline (x 3) = log Subscript 2 Baseline (2 x) Which system of equations can repre

swat32

Equal expressions can be taken equal to an another variable. The system of equations representing the equation is $y = x + 3\\y = 4x + 8$

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

Some properties of logarithm are:

$log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1\\\\ log_a(b) + log_b(c) = log_a(c)$

Log with base e = 2.71828... is written as $\ln(x)$ simply.

Log with base 10 is written as $\log(x)$ simply.

The given equation is:

$\log_4(x+3) = \log_2(2 +x)$

Adding $\log_2(4)$ on both the sides, we get:

$\log_2(4) + \log_4(x+3) =\log_2(4) + \log_2(2 +x) \\\\log_2(x + 3) = log_2(4(2+x))\text{\: \: \: (using first and last property listed)}\\\\x+3 = 8+4x = y(say)$