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2 years ago

Each cement block weighs 4 3/5 pounds. How much do 3 cement blocks weigh in total?

Mathematics

1 answer:

natali 33 [55]2 years ago

3 0

Answer:

13 4/5 pounds

Step-by-step explanation:

You multiply 4 3/5 by 3, which equals 13.8, which equals 13 4/5 pounds.

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Ms Thomas drove at a constant rate for 45. She drove 39 miles during that time. If distance is determined by the equation d=rt w

Cerrena [4.2K]

Answer:

Ms. Thomas was driving at constant rate of 52 miles/hour.

Step-by-step explanation:

Given:

Total time to travel (t) = 45 minutes

Distance drove (d) = 39 miles

we need to find the constant rate in miles per hour at which she was driving.

Solution:

Now we know that;

We need to find constant rate at miles per hour;

But time is given in minutes.

So we will convert minutes into hour by dividing by 60 we get;

time $t =\frac{45}{60}= 0.75\ hrs$

Now we know that;

Distance is equal to rate times time.

framing in equation form we get;

distance $d =rt$

rate $r= \frac{d}{t} = \frac{39}{0.75}= 52 \ mi/hr$

Hence Ms. Thomas was driving at constant rate of 52 miles/hour.

6 0

3 years ago

(2+x)dy/dx=3y need help

den301095 [7]

$(2+x) \frac{dy}{dx} =3y$
$\frac{1}{3y} dy= \frac{1}{2+x} dx$
$\int { \frac{1}{3y} } \, dy = \int { \frac{1}{2+x} } \, dx$
$\frac{1}{3}\ln(3y) = \ln(2+x) + C$
(raise both to the power e): $e^{ \frac{1}{3}\ln(3y)}=e^{\ln(k(2+x))}$
$(3y)^ \frac{1}{3} =k(2+x)$
$3y=k(2+x)^3$
$y= k(2+x)^3$

5 0

3 years ago

Look at the graph below.

romanna [79]

Where is the graph? Because it would be a lot easier to answer this if you could show a picture of the graph

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3 years ago

Read 2 more answers

Pls help with my homework I need help

shusha [124]

Answer:

tan G = 1.6071

Step-by-step explanation:

tan G = 45/28

tan G = 1.6071

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2 years ago

the average monthly precipitation for dallas for oct, nov, and dec is 3.47 in. If 2.88 in. falls in oct and 3.13 in. falls in no

saveliy_v [14]

Answer:

Step-by-step explanation:

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3 years ago