Answer:
Places in binary coding
1 - 2 - 4 - 8 - 16 - 32 - 64 - 128 - 256 - 512 - 1024 - 2048
2483 - 2048 = 435 there is 1 in the 2048 position
435 - 256 = 179 there is 1 in the 256 position
179 - 128 = 51 there is 1 in the 128 position
51 - 32 = 19 there is 1 in the 32 position
19 - 16 = 3 there is 1 in the 16 position
3 - 2 = 1 there is 1 in the 2 position
1 - 1 = 0 there is 1 in the 1 position
10011011 0011 would be the binary result
Check:
2048 + 0 + 0 + 256 + 128 + 0 + 32 + 16 + 0 + 0 + 2 + 1 = 2483
5 : 5, 10, 15, 20, 25
6 : 6, 12, 18, 24, 30
The answer is
f(n)=6(3^n-1)
Which is the third option
Explanation :
Plug in the n values in the equation
Example : 6(3^1-1)
3^0=1
6(1)=6
I hope I helped
Area of sector
so the area = 37.71 square metre
Heya!
Here is your answer:
6a²-15a-8a+20
= 3a(2a-5) -4(2a-5)
= (3a-4)(2a-5)
:)
