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Mathematics

1 answer:

MaRussiya [10]3 years ago

4 0

If he draws at random there is a 3/7 percent chance that he will pull an odd number Here's why :

There are seven numbers making the denominating factor 7 and out of those 7 factors only 3 of them are odd numbers
Making the nominating factor 3 so it should look like this
3/7 because three off the seven numbers are odd
so therefore there is a 3/7 percent chance at pulling an odd number.

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Step-by-step explanation:

$7.\\(3s^2+7s+2)+(5s^2+9s-1)=3s^2+7s+2+5s^2+9s-1\\\\\text{combine like terms}\\\\=(3s^2+5s^2)+(7s+9s)+(2-1)\\\\=8s^2+16s+1$

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$11.\\n-the\ number\\\\n^2=n+6\qquad\text{subtract}\ n\ \text{and}\ 6\ \text{from both sides}\\\\n^2-n-6=0\\\\n^2+2n-3n-6=0\\\\n(n+2)-3(n+2)=0\\\\(n+2)(n-3)=0\iff n+2=0\ \vee\ n-3=0\\\\n+2=0\qquad\text{subtract 2 from both sides}\\n=-2\\\\n-3=0\qquad\text{add 3 to both sides}\\n=3$