1. n/2-1/3-1=1/6
n/2=1/6+1/3+1
n/2=1/6+2/6+6/6
n/2=9/6=3/2
n=3/2*2=3
check: abs(3/2-1/3)-1=1/6, abs(9/6-2/6)-1= 1/6, 7/6-1=1/6, 1/6 =1/6
3 is a root
2. -(n/2-1/3)-1=1/6
-n/2+1/3-1=1/6
-n/2-2/3=1/6
-n/2=1/6+2/3
-n/2=1/6+4/6
-n/2=5/6
n=-2*5/6=-5/3=-1 2/3
check : abs((-5/3)/2-1/3) -1=1/6
abs(-5/6-1/3) -1 =1/6, abs(-5/6-2/6) -1=1/6, abs (-7/6)-1=1/6, 7/6-1=1/6, 1/6=1/6
so -5/3 or -1 2/3 is also root
so two roots 3 and -5/3(that can be written as -1 2/3)
Given, 18 pumps----2170 tonnes----10*7 hrs.
So, 16 pumps-------2170 tonnes----10*7*18/16 hrs.
And, 16 pumps-------1736 tonnes----10*7*(18/16)*(1736/2170)hrs. = 63 hrs.
So, no. of days req.= 63/9 = 7 days
Answer:
280 mangoes
Step-by-step explanation:
sum the parts of the ratio, 7 + 11 = 18 parts
Divide the total by 18 to find the value of one part of the ratio.
720 ÷ 18 = 40 ← value of 1 part of the ratio , then
7 × 40 = 280 ← number of mangoes