Answer:
The energy stored in ATP at one location is released from ATP when the terminal phosphate bond is broken. In this process a phosphate group is detached to yield inorganic phosphate and ADP and results in the liberation of 7.3 kcal/mol (under standard conditions).
Explanation:
Answer:
this mutation may change the open reading frame of the resulting RNA sequence and its final product, which is a protein in the case that this gene is used to synthesize a messenger RNA (mRNA) sequence
Explanation:
During the transcription, a region of DNA named 'gene' is used as template to produce an RNA molecule, typically a primary transcript of mRNA (pre-mRNA). Subsequently, this pre-mRNA suffers a process named RNA processing in order to generate a mature mRNA which is finally used to create a protein by a process called translation. If a deletion occurs during transcription, it may change the open reading frame (ORF) of the resulting mRNA when the mutation occurs in an exon of the protein-coding gene (i.e., occurs a frameshift mutation), while this deletion may not have any effect if it is localized within the introns which are removed during RNA processing. A frameshift mutation will change the amino acids that are added to the nascent polypeptide chain during translation.
The correct option is this: MARIA'S WATER USE IS CONSUMPTIVE.
Water use can be consumptive or non consumptive. Consumptive water use refers to the process of using water in such a way that the water used can not be returned to the water resources system.
The water that Maria used to shower, the one she drank and the one she used to wash her laundry are waste water, which are not returned to the central water resources system, thus, Maria's water use is consumptive.
Answer:
10 m/s/s or m/s²
Explanation:
Acceleration can be calculated by using the formula;
a = v - u/t
Where;
a = acceleration (m/s²)
v = final velocity (m/s)
u = initial velocity (m/s)
t = time (s)
In other terms, acceleration (a) can be represented as ∆V/t.
According to this question, a ball accelerates from 10 m/s (u) to 30 m/s (v) in 2 seconds. Hence, the acceleration of the ball is as follows:
a = 30 - 10/2
a = 20/2
a = 10m/s².
Answer:
The correct answer is - both pathways glycolysis pathway and gluconeogenesis pathway.
Explanation:
The enzyme triose phosphate isomerase includes the Glyceraldehyde 3 P dehydrogenase. It is one of the enzymes used in glycolysis as well as gluconeogenesis. These enzymes catalyze the conversion of glyceraldehyde to 1,3 bis phosphoglycerate.
Thus, the correct answer is - both pathways glycolysis pathway and gluconeogenesis pathway.
