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Sliva [168]
3 years ago
7

What is the probability of rolling a 6 with a six sided die?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0
The probability of landing a 6 with a six sided die is 1/6
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Please help ASAP 30 pts + brainliest to right/best answer
azamat

Answer:


Step-by-step explanation:There's nothing there to solve. But you can simplify the expression.-- The difference of two logs is the log of the quotient. log₆(25) - log₆(5) = log₆(25/5) = log₆(5) .That may be all you can do with it.If they want you to go ahead and actually find the value of log₆(5) ...I don't remember how to do that. If it was log₁₀(5) or ln(5) ,those would be easy, because they're right on your calculator.But the log to the base of (anything else other than 10 or 'e') takesan additional step, which I don't remember. brainliest pls?



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3 years ago
What is the value of y?
AlexFokin [52]

Answer:

60°

Step-by-step explanation:

All the sides are of equal length, 12,12,12 , 60,60, ?, so it is 60

4 0
3 years ago
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Write a whole number that round to 800 if we rounding to nearest ten thousand
LUCKY_DIMON [66]
790  i think sorry if it's wrong :/
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3 years ago
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5x +3x = (4x - 5)-2 plz help tysm im really struggling and my teacher will make me present this problem since im not so bright p
tensa zangetsu [6.8K]

Answer:

x=1.6

Step-by-step explanation:

first follow PEMDAS

so you multiply -2 into the parentheses

-8x and +10

so now it is

5x+3x=-8x+10

add 5x +3x

get 8x

then we have

8x=-8x+10

add -8 to the other side

get 16x

so now 16x=10

divide 16 by 10

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5 0
3 years ago
The probabilities that a customer selects 1, 2, 3, 4, or 5 items at a store are 0.32, 0.12, 0.23, 0.18, and 0.15, respectively.
Andrew [12]

Answer:

a. This is a probability distribution as ∑pi=1

b. 2.72

c. 1.45

Step-by-step explanation:

a. To verify the probability distribution we simply add all given probabilities and see whether they sums up to 1 or not. According to definition of probability distribution sum of probabilities should be 1 so,

∑pi=0.32+0.12+0.23+0.18+0.15=1

Hence it is verified that given distribution is a probability distribution.

b. Mean number of items selected= E(x)= ∑x*p(x)

here x =1,2,3,4,5 and p(x)=0.32,0.12,0.23,0.18,0.15.

mean number of items=1*0.32+2*0.12+3*0.23+4*0.18+5*0.15=2.72

c. standard deviation of number of items=sqrt[(∑x²*p(x))-(∑x*p(x))²]

∑x²*p(x)=1*0.32+4*0.12+9*0.23+16*0.18+25*0.15=9.5

(∑x*p(x))²=(2.72)²=7.4

standard deviation of number of items=sqrt[(∑x²*p(x))-(∑x*p(x))²]=sqrt(9.5-7.4)=sqrt(2.1)=1.45

6 0
3 years ago
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