Please help i’m giving out brainliest || Q1

A survey of a group of seventh graders and a group of teachers at a local middle school asked how many siblings they each have.

kvasek [131]

Answer:

The center of the data is to the right of the dot plot for both teachers and students.

There is a greater variation in the data for teachers than for students.

The center of the data for students has a value less than that of the center of the data for teachers.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

14. A square has a perimeter of 36 units. One vertex of the square is located at (3,5) on the coordinate grid, What could be the

Irina18 [472]

Answer:

For a square of side length L, the perimeter is:

P = 4*L

Then if the perimeter of our square is 36 units, we have:

36 units = 4*L

(36 units)/4 = L = 9 units.

Now we know that one vertex of the square is located at (3, 5)

Then another vertex of the square can be at:

A distance of 9 units of this point (such that these vertices are connected by one side of the square)

Some examples can be:

(3 + 9, 5) = (12, 5)

or

(3, 5 + 9) = (3, 14)

These are the simpler options, there are a lot of other possible points that can be another vertes (we can have a circle of radius 9 units centered in the point (3, 5), all these points can be another vertex of the square).

We also can have a vertex that is connected by the diagonal, this point can be:

(3 + 9, 5 + 9) = (12, 14)

or

(3 - 9, 5 - 9) = (-6, -4)

Again, there are a lot of other possible points that can be this vertex (A circle of radius √2*9 units centered in the point (3, 5)).

6 0

3 years ago

What is true about this graph? Select all that apply.

schepotkina [342]

Answer:

E, B and A

Step-by-step explanation:

8 0

3 years ago

Help pls I'll give 25 points

RideAnS [48]

Answer:

$\text{C. }60$

Step-by-step explanation:

<u>Question from image</u>:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the <em>x</em> marks where it cannot be.

$\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}$

Let's start with the first position:

$\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}$

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in $3!=6$ ways. Therefore, there are $4\cdot 6=\boxed{24}$ possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

$\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}$

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in $3!=6$ ways. Therefore, there are $3\cdot 6=\boxed{18}$ possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are $3!=6$ ways to rearrange the remaining 3 digits for a total of $2\cdot 6=\boxed{12}$ possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still $3!=6$ ways to rearrange the remaining three numbers. Therefore, there are $1\cdot 6=\boxed{6}$ possible numbers when 1 is the fourth digit of the number.

Thus, there are $24+18+12+6=\boxed{60}$ numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.