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Alja [10]
3 years ago
15

Write 18,801,310 in expanded form using exponents

Mathematics
1 answer:
Gnesinka [82]3 years ago
8 0

Answer:

Quite a long one, here it is:

18,801,310 = (1 x 10^{9}) + (8 x 10^{8}) + (0 x 10^{7}) + (8 x 10^{6}) + (0 x 10^{5}) + (1 x 10^{4}) + (0 x 10^{3}) + (3 x 10^{2}) + (1 x 10^{1}) + (0 x 10^{0})

Additionally, if you can't copy that and you needed to use the caret key (^) instead of the exponent image on brainly here it is:

18,801,310 = (1 x 10^9) + (8 x 10^8) + (0 x 10^7) + (8 x 10^6) + (0 x 10^5) + (1 x 10^4) + (0 x 10^3) + (3 x 10^2) + (1 x 10^1) + (0 x 10^0)

<u>Hope this helps and have a nice day!</u>

<u />

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(Refer to the attached image)​
RSB [31]

Answer:

missing side: 133 cm

Explanation:

Provided <u>2 length sides</u> and <u>one angle</u> also need to find <u>one missing side</u>.

So, use cosine rule:

⇒ a² = b² + c² - 2bc cos(A)

<u>Insert values</u>

⇒ g² = 166² + 147² - 2(166)(147) cos(50)

⇒ g² = 17794.3935

⇒ g = √17794.3935

⇒ g = 133.3956

⇒ g = 133          (rounded to nearest whole number)

8 0
1 year ago
4 - ⅛w &lt; 16<br> can someone plz anwser and show work
padilas [110]

Step-by-step explanation:

so first convert it into an algebraic equation

4 - ⅛w = 16

⅛w = 16-4

⅛w = 12

w=12÷ \frac{1}{8}

w=12×8=96

check: 4 - ⅛(96)=4-12=-8

-8<16 (-8 less than 16)

please mark brainliest

8 0
2 years ago
When the factors of a trinomial are (x+ p) and (x + q) then the coefficient of the x-term in the trinomial is:
Eva8 [605]
The coefficient of x in this case is 1. (x*x = x^2)
4 0
3 years ago
Read 2 more answers
Find y’ for y=7sec^3x
laiz [17]
Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.

We then multiply everything together to simplify:

sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes

3x^2 * sin(x^3)/(cos(x^3))^2

and multiplying the constant 7 from the beginning:

7 * 3x^2 = 21x^2, so...

our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2


6 0
3 years ago
Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)
Arlecino [84]
y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt

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Now the arc length over an arbitrary interval (a,b) is

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But before we compute the integral, first we need to make sure the integrand exists over it. x^{3/2} is undefined if x, so we assume a\ge0 and for convenience that a. Then

\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)
6 0
3 years ago
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