Answer:
0.7881 = 78.81% probability that the percent of 18 to 34 year olds who check social media before getting out of bed in the morning is, at most, 32.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

Find the probability that the percent of 18 to 34 year olds who check social media before getting out of bed in the morning is, at most, 32.
This is the pvalue of Z when X = 32. So



has a pvalue of 0.7881
0.7881 = 78.81% probability that the percent of 18 to 34 year olds who check social media before getting out of bed in the morning is, at most, 32.
Answer:
The probability of assembling the product between 7 to 9 minutes is 0.50.
Step-by-step explanation:
Let <em>X</em> = assembling time for a product.
Since the random variable is defined for time interval the variable <em>X</em> is continuously distributed.
It is provided that the random variable <em>X</em> is Uniformly distributed with parameters <em>a</em> = 6 minutes and <em>b</em> = 10 minutes.
The probability density function of a continuous Uniform distribution is:

Compute the probability of assembling the product between 7 to 9 minutes as follows:


![=\frac{1}{4}\times [x]^{9}_{7}\\](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B4%7D%5Ctimes%20%5Bx%5D%5E%7B9%7D_%7B7%7D%5C%5C)


Thus, the probability of assembling the product between 7 to 9 minutes is 0.50.
Answer:
1. x = 22
2. x = 38
3. x = 24
Step-by-step explanation:
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Answer:
y = 7
Step-by-step explanation:
on that equation there is the point (-5 , 7)