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atroni [7]
3 years ago
11

Whatis the value of x in the equation x - y = 30, when y = 15? 8

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
4 0

Answer:

x=45

Step-by-step explanation:

30+15=45

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•• quilt squares are cut on the diagonal to form triangular quilt pieces the hypotenuse of the resulting triangle is 10 inches l
qwelly [4]
<span>1) The problem says that the quilt squares are cut on the diagonal to form triangular quilt pieces. Then, the triangle pieces have angles of 45°, and the legs have the same lenght. So, you can solve the exercise by applying </span><span>the Pythagorean Theorem:
</span>
 h²:s²+s²
 h²=2s²
 h²/2=s²
 s=√(h²/2)

 "h" is the hypotenuse (h=10 inches) and "s" is the length of the sides.

 When you substitute the value of the hypotenuse into the formula s=√(h²/2), you obtain the sides length:

 s=√(h²/2)
 s=√(10²/2)
 s=5√2

 What is the side length of each piece? 

 The answer is: 5√2


 2)Tan(α)=Opposite/Adjacent

 α=30°
 Opposite=17
 Adjacent=x

 When you substitute these values into Tan(α)=Opposite/Adjacent, you obtain:

 Tan(α)=Opposite/Adjacent
 Tan(30°)=17/x
 x=17/Tan(30°)
 x=17√3

 Sin(α)=Opposite/Hypotenuse

 α=30°
 Opposite=17
 Hypotenuse=y

 Then, you have:

 Sin(30°)=17/y
 ySin(30°)=17
 y=17/Sin(30°)
 y=34
5 0
3 years ago
Solve for x in the triangle. Round your answer to the nearest tenth.
alekssr [168]

Answer: 3.9

Step-by-step explanation:

<u>sin 34  </u>                 <u>     x   </u>  

 1                               7

Cross multiply and divide to get 3.9

6 0
3 years ago
PLEASE HELP PRE ALGEBRA EASY 10 POINTS
Advocard [28]
What I’m support to fine it in the graph or find the slop, solve for x or y???? Put the whole question so I can help you
8 0
2 years ago
For which equation would x = 5 be a solution?
tresset_1 [31]

Answer:

The second option.

3x + 6 = 21.

Step-by-step explanation:

3x + 6 = 21.

If x = 5, plug it in.

3 · 5 + 6 = 21

15 + 6 = 21

Hope this helps,

Davinia.

7 0
2 years ago
Find the circumference of a circle that has an area of 452.16 square meters. (Use 3.1416 as the value of π.)
laila [671]
\bf \textit{area of a circle}\\\\&#10;A=\pi r^2\quad &#10;\begin{cases}&#10;r=radius\\&#10;-----\\&#10;A=452.16&#10;\end{cases}\implies 452.16=\pi r^2\implies \cfrac{452.16}{\pi }=r^2&#10;\\\\\\&#10;\boxed{\sqrt{\cfrac{452.16}{\pi }}=r}\\\\&#10;-------------------------------\\\\&#10;\textit{circumference of a circle}\\\\&#10;C=2\pi r\qquad \qquad \implies C=2\pi \left( \boxed{\sqrt{\cfrac{452.16}{\pi }}} \right)

so, is just that product, recall to use "<span>3.1416 as the value of π".</span>
7 0
3 years ago
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