Answer:
Step-by-step explanation:
Prove: That the sum of the squares of 4 consecutive integers is an even integer.
An integer is a any directed number that has no decimal part or indivisible fractional part. Examples are: 4, 100, 0, -20,-100 etc.
Selecting 4 consecutive positive integers: 5, 6, 7, 8. Then;
= 25
= 36
= 49
= 64
The sum of the squares = 25 + 36 + 49 + 64
= 174
Also,
Selecting 4 consecutive negative integers: -10, -11, -12, -13. Then;
= 100
= 121
= 144
= 169
The sum of the squares = 100 + 121 + 144 + 169
= 534
Therefore, the sum of the squares of 4 consecutive integers is an even integer.
Answer:
Yes
Step-by-step explanation:
74/e < 12
Since e is in the denominator, e can not be 0.
If e > 0,
74/e < 12
74 < 12e
e > 74/12
e < 37/6
If e < 0,
(When you multiply by e, which is a negative value, inequality reverses)
74 > 12e
e < 74/12
e < 37/6
If you are saying:
(3/12) - (8/12)
Then since their denominators are the same we can subtract the numerators to get our answers.
3 - 8 = -5
Following the rule of adding and subtracting fractions, the denominators will not change unless they are different.
So: (3/12) - (8/12) = -5/12
Answer:
729x^12
Step-by-step explanation:
3x^2*3x^2*3x^2*3x^2*3x^2*3x^2
