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storchak [24]
3 years ago
15

Which of the following does ((NOT)) Describe a single-displacement reaction?

Chemistry
1 answer:
Tpy6a [65]3 years ago
4 0

Answer:

The correct answer is option C.

Explanation:

Single replacement reaction : It is a type of chemical reaction in which element exchange their position with the position of another element in its compound molecule.

AB+C\rightarrow CB+A

It is also called redox reaction because one element getting oxidized and another one getting reduced.

Hence, the correct answer is option C.

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The gravitational strength on Earth is greater than the gravitational strength on Mars. Which statement is correct?
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<em>I</em><em> think</em><em> option</em><em> </em><em>(</em><em>b)</em><em> </em><em>is</em><em> right</em><em> answer</em>

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We expect the enthalpy of cumbustion of two isomers to be _________. The molecular formulas of two molecules are _____, so the b
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We expect the enthalpies of combustion of two isomers to be different.

The molecular formular of the two molecules are very similar.

So the balanced chemical equation for the two combustion reactions are the same.

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The difference will be in the standard enthalpies of formation of the two combustion products.

The rod-shaped n- octane has vibrational and rotational motion possible more than the almost spherical neoprene.

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What is a precipitation <br>reaction?​
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4 0
3 years ago
Consider 2 NOCl(g) \Longleftrightarrow⟺ 2 NO(g) + Cl2 (g) At 25oC under conditions other than equilibrium, there are 1.20 moles
nekit [7.7K]

Answer:

a) Q = 6.1875x10⁻³

b) The direction of the reaction is to form the products.

c) [Cl₂]e = 0.094 M

[NO]e =  0.190 M

[NOCl]e = 0.140 M

Explanation:

a) Q is the reaction quotient, and for a generic reaction aA + bB ⇄ cC + dD it is

Q = \frac{[C]^cx[D]^d}{[A]^ax[B]^b}

Which is the same equation for Kc, but in Kc expressions, the concentrations are in the equilibrium. Q is calculated at any time. So, for the reaction given

2NOCl(g) ⇄ 2NO(g) + Cl2(g)

Q = \frac{[Cl2]x[[NO]^2}{[NOCl]^2}

[Cl₂] = 0.220/5.00 = 0.044 M

[NO] = 0.450/5.00 = 0.090 M

[NOCl] = 1.20/5.00 = 0.240 M

Q = (0.044)x(0.090)²/(0.240)²

Q = 6.1875x10⁻³

b) Q < Kc, which means that there are fewer products to what are needed to the equilibrium. So the direction of the reaction is to form the products.

c)

2NOCl(g) ⇄ 2NO(g) + Cl2(g)

0.240           0.090      0.044         <em>Initial</em>

-2x                 +2x          +x             <em> Reacts</em> (stoichiometry is 2:2:1)

0.240-2x   0.090+2x   0.044+x    <em> Equilibrium</em>

Kc = \frac{(0.044+x)x(0.090+2x)^2}{(0.240 - 2x)^2}

1.86x10^{-1} = \frac{(0.044+x)*(8.1x10^{-3} +0.36x + 4x^2)}{(0.0576 - 0.96x +4x^2)}

3.564x10⁻⁴+0.01584x+0.176x²+8.1x10⁻³x+0.36x²+4x³ = 0.010714-0.17856x+0.744x²

4x³ - 0.208x² + 0.2025x - 0.01036 = 0

Solving this third grade equation in a computer program:

x = 0.05 M

So:

[Cl₂]e = 0.044 + 0.05 = 0.094 M

[NO]e = 0.090 + 2x0.05 = 0.190 M

[NOCl]e = 0.240 - 2x0.05 = 0.140 M

7 0
3 years ago
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