All categories

3 years ago

What values of x make the expression (x+4)(x-6) negative

1 answer:

8 0

Anything under 6 would make it negative as a positive times a negative equals a negative basically the x+4 doesn't matter as long as it's positive and the x-6 as long as that's negative it doesn't matter the area in which they have to be is -3 to 5

You might be interested in

What is 10* 3.8 exponent of 6 in scientific notation

Tju [1.3M]

3.8 x 3.8 x 3.8 x 3.8 x 3.8 x 3.8 = 3010.9363843010.936384 x 10 = 30109.36384
30109.36384 = 3.01094 × 10^4


hope this helps

8 0

3 years ago

The pen for Ruth’s dog is 7 feet long and 6 1/2 feet wide. Her friend Ralph’s dog pen is 14 feet long and 6 1/2 feet wide. How m

Mkey [24]

Answer:

2 times larger

Step-by-step explanation:

Ralph's pen is 91 feet long

ruths is 45.5

Easily makes 91

7 0

2 years ago

Read 2 more answers

Truck A costs $600 more that Truck B. However, it burns 0.06 gallon/mile compared to 0.07 gallon/mile for truck B. Both trucks h

qwelly [4]

Answer:

1,778

Step-by-step explanation:

Let C and S represent the cost and salvage value of Truck B, respectively. Let X represent the number of miles per year that answers the question.

Truck A's cost for 10 years is ...

A = C+600 +(0.06)(2.25)(10X) -(S+200)

Truck B's cost for 10 years is ...

B = C +(0.07)(2.25)(10X) -S

We want to find X such that Truck A's cost is lower, so ...

C -S +1.35X +400 < C -S +1.575X

400 < 0.225X

1777 7/9 < X

1778 miles driven per year (or more) makes Truck A a better option.

5 0

3 years ago

Which is the graph of y = 2(x - 3)^2+2

makvit [3.9K]

go to demos. com press graphing calculator then type it in

5 0

3 years ago

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2

Basile [38]

Answer:

$f(x) = x^3 - 2x^2 -3x + 6$

Step-by-step explanation:

According to the Factor Theorem, if (x - k) is a factor of a polynomial P(x), then P(k) must equal zero.

We are given that a polynomial function has the zeros 2, √3, and -√3. So, we can let k = 2, √3, -√3.

So, according to the Factor Theorem, P(2), P(√3) and P(-√3) must equal 0.

Testing each choice, we can see that only A is true:

$\displaystyle f(x) = x^3 - 2x^2 - 3x + 6$

Testing all three values yields that:

$\displaystyle \begin{aligned} f(2) &= (2)^3 - 2(2)^2 -3(2) + 6 \\ &= (8) - (8) -(6) + (6) \\ &= 0\stackrel{\checkmark}{=}0 \\ \displaystyle f(\sqrt{3}) &= (\sqrt{3})^3 - 2(\sqrt{3})^2 - 3(\sqrt{3}) + 6 \\ &=(3\sqrt{3}) -(6)-(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \\ f(-\sqrt{3}) &= (-\sqrt{3})^3 - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 \\ &=(-3\sqrt{3}) -(6)+(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \end{aligned}$

Hence, our answer is A.

3 0

3 years ago