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3 years ago

Analyze: The first shell can hold a maximum of two electrons. How does this explain the valence of hydrogen

Chemistry

1 answer:

chubhunter [2.5K]3 years ago

4 0

Answer:

See explanation

Explanation:

Hydrogen has a valency of +1 or -1. Its electronic configuration is 1s1.

The 1s sub-level (first shell) is known to hold two electrons. This means that hydrogen may either loose this one electron in the 1s level to yield H^+ or accept another electron into this 1s level to form H^- (the hydride ion).

The formation of the hydride ion completes the 1s orbital.

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In an experiment, a solution required 30. 05 g of nacl, 50. 0 g of , and 0. 4006 g of mgso4. Using the correct number of signifi

Radda [10]

When the use of significant figures and rounding up is applied correctly the mass of the mixture will be 80.5 g.

In cases of addition or subtraction, only the last significant figure of every number is taken into account.

In 30.05, this is 5, in the hundredths. When we look at 50.0, the last significant figure is 0, and it is in the tenths. And in 0.4006, the last significant figure is 6, in the ten thousandths. Of these three, the 0 from 50.0 is in the leftmost position, which means that the last significant figure of the result needs to be in the same position (in the tenths).

Moving onto the actual algebraic operation:

30.05 g + 50.0 g + 0.4006 = 80.4506 g

As we established, the last significant figure should be in the tenths, and we will have to round up 4 to 5 (trailing numbers are greater than 0), which means that the resulting mass will be 80.5 g.

You can learn more about significant figures here:

brainly.com/question/14804345

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7 0

2 years ago

The Group 8A(18) elements The Group 8A(18) elements are unreactive and are rarely found in combination with other elements. are

valentina_108 [34]

Answer: Option (a) is the correct answer.

Explanation:

It is known that elements which have completely filled octet when they are present in neutral state then they do not need to gain or lose an electron. Hence, the element becomes unreactive in nature.

For example, neon is a noble gas whose atomic number is 10 and its electronic distribution is 2, 8. As they have completely filled orbitals so they do not react with other elements.

As a result, they are rarely found in combination with other elements.

Thus, we can conclude that the Group 8A(18) elements are unreactive and are rarely found in combination with other elements.

5 0

3 years ago

Leaves the cells and joins the bloodstreams as a waste<br> product of respiration?

Naddik [55]

Carbon dioxide leaves as a product of respiration

6 0

4 years ago

Number 8 pls step by stepA sample of gas has a mass of 20.00 g and occupies 44.8 L at STP. What is the molar mass of the gas?

LuckyWell [14K]

A sample of gas has a mass of 20.00 g and occupies 44.8 L at STP. What is the molar mass of the gas?

We know that 1 mol of an ideal gas at STP occupies 22.4 L. So we will use that relationship to find the number of moles of the gas that occupies 44.8 L.

number of moles = 44.8 L * 1 mol/(22.4 L) = 2.00 moles

number of moles = 2.00 moles

Another way of getting the same result is:

STP means that the pressure is 1 atm and the temperature is 273.15 K. And the volume of our sample is 44.8 L

P * V = n * R * T

n = P * V/(R * T)

n = 1 atm * 44.8 L / (0.082 atm*L/mol*K * 273.15 K)

n = 2.00 moles

So two moles of an ideal gas occupies 44.8 L at STP.

The mass of the sample is 20.00 g and we have 2 moles. So the molar mass is:

molar mass = (mass of sample)/(number of moles of the sample)

molar mass = 20.00 g/(2.00 moles)

molar mass = 10.0 g/mol

Another way of solving it:

Since the mass of two moles of our gas is 20.00 g, we can find the mass of 1 mol by solving this:

2.00 moles of gas ______ 20.00 g

1.00 mol of gas _____ x = ?

x = 1.00 mol * 20.00 g/2.00 moles = 10.0 g

So the mass of 1 mol is 10.0 g. Then the molar mass is 10.0 g/mol.

Answer: the molar mass of the gas is 10.0 g/mol

7 0

1 year ago

Balance the following equations: (c) H2(g)+I2(s)⟶HI(s)H2(g)+I2(s)⟶HI(s)

kenny6666 [7]

Answer: $H_2(g)+I_2(g)\rightarrow 2HI(s)$

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Thus in the reactants, there are 2 atoms of hydrogen and 2 atoms of iodine .Thus there has to be 2 atoms of hydrogen and 2 atoms of iodine in the product as well. Thus a coefficient of 2 is placed in front of HI.

The balanced chemical reaction is:

$H_2(g)+I_2(g)\rightarrow 2HI(s)$

6 0

4 years ago