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3 years ago

12

The speed of revolution of particle going around a circlr is doubled and its angular speed is havled. What happen to the centrip

etal acceleration?
a) unchanged
b) doubles
c) halves
d) becomes four times

1 answer:

Zarrin [17]3 years ago

7 0

Answer: The correct answer is C

Explanation:

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3 years ago

We want to hang a thin hoop on a horizontal nail and have the hoop make one complete small-angle oscillation each 2.0 s. What mu

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Answer:

Explanation:

Given that the hoop makes one complete oscillation in 2s, this implies that the period of oscillation is 2s

Then,

T = 2s

Let Mass of the thin hoop be M

Let Radius of the hoop be R

Moment of inertial of a hoop is

I = MR²

Period of a physical pendulum of small amplitude is given by

T = 2π √(I / Mgd)

Where,

T is the period in seconds

I is the moment of inertia in kgm²

M is the mass of the hoop

g is the acceleration due to gravity

g = 9.8m/s²

d is the distance from rotational axis to center of of gravity

Therefore, d = R

Then, applying the formula

T = 2π √ (I / MgR)

So, we know that

I = MR²

Then,

T = 2π √( MR² / MgR)

T = 2π √(R/g)

Make R subject of formula

Square both sides

T² = 4π²(R/g)

T²g = 4π²R

Then, R = T²g / 4 π²

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R = 2² × 9.8 / 4π²

R = 0.993m

Then, the radius of the hoop is 0.993m

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3 years ago

A space probe is built with a mass of 1700 pound-mass [lbm] before launch on Earth. The probe is powered by four ion thrusters,

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mass of the space probe is given as

m = 1700 lbm = 771.12 kg

each thrust will apply a net force

$F = 225 milli N = 0.225 N$

now we will have

$v = at$

$v = \frac{F}{m}*t$

given that we have final speed v = 420 miles/minute

we need to convert it into m/s

$v = 420\frac{miles}{min}*\frac{1609 m}{1 miles}*\frac{1 min}{60 s}$

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now from above equation

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<em>so it will require 63.8 weeks to reach the given speed</em>

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4 years ago

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