Technology is the application of science to make products that are useful to people. True or False

In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background sign

VladimirAG [237]

This question is incomplete, the complete question is;

In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background signal level is 13 mV, the signal is 91 mV with no attenuator and is 25 mV with an attenuator in place. Calculate pt /pi

Answer: the pt/pi is 15.3846%

Explanation:

Given that;

Background = 13 mV

corrected signal = 91 mV - 13 mV = 78 mV

with attenuator = 25 mV - 13 mV = 12 mV

pt/pi = ?

so pt/pi = 12/78 × 100

= 15.3846%

Therefore the pt/pi is 15.3846%

3 0

3 years ago

What net is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/second^2 (assume a flat,fr

stich3 [128]

Newton's 2nd Law of Motion: Force = (mass) · (acceleration)

Do I need to go any further ?

I get 575.25 Newtons .

Oh ! Look at that ! Right there at the top, it says "Using Newton's Second Law". This might have suggested to you that maybe you could solve the problem by using Newton's Second Law.

8 0

3 years ago

What is kinetic energy of a 7.26kg bowling ball that is rolling at a speed of 2m/s?

sergey [27]

Kinetic energy is the energy possessed by an object when that object is moving in space. The higher the mass of an object or higher the speed of an object the higher the kinetic energy will be.

So to calculate the Kinetic Energy we can use the following formula

K.E=(1/2)*m*v^2

Inserting the values in formula gives:

K.E=1/2*7.26*2^2

14.52J

This is the final answer which gives the kinetic energy of the ball.

8 0

3 years ago

A 3.50 kg block is pushed along a horizontal floor by a force of magnitude 15.0 N at an angle θ = 30.0° with the horizontal. The

Crank

Answer :

The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².

Explanation :

Given that,

Mass of block = 3.50

Angle = 30°

Force = 15.0 N

Coefficient of kinetic friction = 0.250

We need to calculate the frictional force

Using formula of frictional force

$F_{k}=\mu N$

$F_{k}=\mu (F\sin\theta+mg)$

$F_{k}=0.250\times(15\times\sin30^{\circ}+3.50\times9.8)$

$F_{k}=0.250\times41.8$

$F_{k}=10.45\ N$

(II). We need to calculate the block's acceleration

Using newton's second law of motion

$F=ma$

$a=\dfrac{F}{m}$

$a=\dfrac{F\cos\theta-F_{k}}{m}$

$a=\dfrac{15.0\cos30^{\circ}-10.45}{3.50}$

$a=0.73\ m/s^2$

Hence, The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².

8 0

3 years ago

What is the distance covered by a Freely falling object 5 seconds after being dropped ? After 6 seconds?

mario62 [17]

This year is 60 years since I learned this stuff, and one of the things I always remembered is the formula for the distance a dropped object falls:

D = 1/2 A T²

Distance = (1/2) (acceleration) (time²)

The reason I never forgot it is because it's SO useful SO often. You really should memorize it. And don't bury it too deep in your toolbox ... you'll be needing it again very soon. (In fact, if you had learned it the first time you saw it, you could have solved this problem on your own today.)

The problem doesn't tell us what planet this is happening on, so let's make it easy and just assume it's on Earth. Then the 'acceleration' is Earth gravity, and that's 9.8 m/s² .

In 5 seconds:

D = 1/2 A T²

D = (1/2) (9.8 m/s²) (5 sec)²

D = (4.9 m/s²) (25 sec²)

D = 122.5 meters

In 6 seconds:

D = 1/2 A T²

D = (1/2) (9.8 m/s²) (6 sec)²

D = (4.9 m/s²) (36 sec²)

D = 176 meters

5 0

3 years ago