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tiny-mole [99]
3 years ago
7

Nisha was making a list of things that are obtained from plants and Amol was making a list of things that can dissolve in water.

Nisha's List (obtained from plants)- Jute, wood, rubber.
Amol's list (can be dissolved in water)- Vinegar, lemon juice, cooking soda Which of the following could be added to both lists?Immersive Reader
(1 Point)
Oil
Sugar
Cotton
Table Salt
Physics
1 answer:
Allisa [31]3 years ago
6 0

Answer:

Sugar

Explanation:

Nisha's list:                               Amol's list

  Jute                                          Vinegar

  Wood                                       Lemon juice

  Rubber                                   Cooking soda

Nisha's list is made up of things that can be derived from plants. From the list given, oil, sugar and cotton can also be obtained from plants.

Most plant materials are organic matter.

Amol's list is made up of things that can dissolve in water. Sugar and table salt can also be dissolved in water.

Water is able to dissolve these materials because they are polar compounds. One rule of solubility is that like dissolves like.

New list:

Nisha's list:                               Amol's list

  Jute                                          Vinegar

  Wood                                       Lemon juice

  Rubber                                   Cooking soda

  Sugar                                       Sugar

                                   

Only sugar from the list can be added to both lists. It can be obtained from plant and can also dissolve in water.

                                             

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Answer:

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Explanation:

Given:

Thickness of the paperweight cube, x=8.55\ cm

apparent depth from one side of the inbuilt paper in the plastic cube, i=4.02\ cm

apparent depth from the other side of the inbuilt paper in the plastic cube, i'=1.56\ cm

Now as we know that refractive index is given as:

\rm \mu=\frac{real\ depth}{apparent\ depth}

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Since refractive index for an amorphous solid is an isotropic quantity so it remains same in all the direction for this plastic.

\mu=\mu'

\frac{d}{i} =\frac{d'}{i'}

\frac{d}{4.02}=\frac{8.55-d}{1.56}

d=6.1597\ cm

Now the refractive index:

\mu=\frac{d}{i}

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7 0
3 years ago
You are standing on a skateboard, initially at rest. A friend throws a very heavy ball towards you. You can either catch the bal
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To solve this problem we will apply the concept related to the moment, which describes the change in speed in proportion to the body mass. The momentum can be described under the general equation

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Where,

m = mass

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The change in momentum is the difference between the final moment and the initial moment

\Delta p = p_f - p_i

Where,

p_f = Final momentum

p_i = Initial momentum

After catching the ball, the ball comes to rest position and speed of the ball is zero.

p_f = 0

The change in momentum on catching the ball is

\Delta p = 0 - mv

\Delta p = -mv

The momentum during the catching of the ball is

p_i = mv

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p_f = -mv

The momentum is negative since during deflection the ball moves with same speed in opposite direction

\Delta p = -mv-mv

\Delta p = 2-mv

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7 0
3 years ago
A 20-kg child is on top of a slide was pushed down by his brother giving him an initial speed of 2 m/s down the slide. what is t
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Answer:

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4 0
3 years ago
Please help!!
Ronch [10]

Answer:

Explanation:

The distance will be the total distannce covered during the journey.

If you move 3 meters East and move 4 meters north, then the distance will be calculated as;

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d² = 3²+4²

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