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bearhunter [10]
3 years ago
10

What source of renewable energy makes up the vast majority of current global renewable energy resource use, and why is this?

Physics
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

hydropower

Explanation:

hydroelectric power is a domestic source of energy. This automatically allows each state to produce their own energy without being reliant on international fuel sources. It also won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas. This is because it is powered by water.

I hope this helped. sorry it took so long. I was trying to get the right resources 4 you

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In an RC-circuit, a resistance of R=1.0 "Giga Ohms" is connected to an air-filled circular-parallel-plate capacitor of diameter
solniwko [45]

Answer:

\tau = 1\ ms

Explanation:

First we need to find the capacitance of the capacitor.

The capacitance is given by:

C = \epsilon_0 * area / distance

Where \epsilon_0 is the air permittivity, which is approximately 8.85 * 10^(-12)

The radius is 12/2 = 6 mm = 0.006 m, so the area of the capacitor is:

Area = \pi * radius^{2}\\Area = \pi * 0.006^2\\Area = 113.1 * 10^{-6}\ m^2

So the capacitance is:

C = \frac{8.85 * 10^{-12} * 113.1 * 10^{-6}}{0.001}

C = 10^{-12}\ F = 1\ pF

The time constant of a rc-circuit is given by:

\tau = RC

So we have that:

\tau = 10^{9} * 10^{-12} = 10^{-3}\ s = 1\ ms

7 0
2 years ago
Will give brainiest to best answer
Gala2k [10]

Answer:

t

Explanation:

6 0
2 years ago
g In a certain binary-star system, each star has the same mass which is 8.2 times of that of the Sun, and they revolve about the
Mademuasel [1]

To solve this problem it is necessary to apply the concepts related to the Third Law of Kepler.

Kepler's third law tells us that the period is defined as

T^2 = \frac{4\pi^2 d^3}{2GM}

The given data are given with respect to known constants, for example the mass of the sun is

m_s = 1.989*10^{30}

The radius between the earth and the sun is given by

r = 149.6*10^9m

From the mentioned star it is known that this is 8.2 time mass of sun and it is 6.2 times the distance between earth and the sun

Therefore:

m = 8.2*1.989*10^{30}

d = 6.2*149.6*10^6

Substituting in Kepler's third law:

T^2 = \frac{4\pi^2 d^3}{2}

T^2 = \frac{4\pi^2(6.2*149.6*10^9)^3}{2(6.674*10^{-11} )(8.2*1.989*10^30 )}

T=\sqrt{\frac{4\pi^2(6.2*149.6*10^9)^3}{2(6.674*10^{-11} )(8.2*1.989*10^30)}}

T = 120290789.7s

T = 120290789.7s(\frac{1year}{31536000s})

T \approx 3.8143 years

Therefore the period of this star is 3.8years

7 0
3 years ago
If you know this please help
Ainat [17]

Answer:

b.

Explanation:

It's b I sis thebksqjwnsx0qkqnsnd991isnd

3 0
3 years ago
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Which of the following is true regarding the speed of earthquake waves?
Levart [38]

Answer:

p waves travel faster than s waves and surface waves

4 0
3 years ago
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