Given profit,
p(t)=0.4t^2+5.3t-8
After the first year, t=1
p(1)=0.4*(1^2)+5.3*1-8=-2.3
Answer: the annual loss of the coffee shop after the first year (i.e. the second year) is $2,300.
P(t)=500(1+4t/(50+t^2 ))
P'(t) = 500 [(50+t^2).4 - 4t.2t]/(50+t^2)^2
by the quotient rule
500 (-4t^2 + 200)/(t^2 + 50)^2
Hence
P'(2) = 500 . (-16 + 200)/54^2 ~= 31.6
First, subtract 63 from 75 to find out how much it decreased.
75 - 63 = 12
Divide 12 by 75.
12 / 75 = 0.16
In percents, that is 16%.
He spent 16% less this month.
Hope this helps!
I actually think its b cause it can't be d (thats obvious) yh........but i might be wrong