Answer:Measure of angle X=140 degrees and Measure of angle Y= 94 degrees.
Step-by-step explanation:
Answer:
The value is 
The correct option is a
Step-by-step explanation:
From the question we are told that
The margin of error is E = 0.05
From the question we are told the confidence level is 95% , hence the level of significance is

=> 
Generally from the normal distribution table the critical value of is

Generally since the sample proportion is not given we will assume it to be

Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20%5C%5E%20p%20%281%20-%20%5C%5E%20p%20%29%20)
=> ![n = [\frac{ 1.96 }{0.05} ]^2 *0.5 (1 - 0.5)](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7B%201.96%20%7D%7B0.05%7D%20%5D%5E2%20%2A0.5%20%281%20-%200.5%29%20)
=> 
Generally the margin of error is mathematically represented as

Generally if the level of confidence increases, the critical value of
increase and from the equation for margin of error we see the the critical value varies directly with the margin of error , hence the margin of error will increase also
So If the confidence level is increased, then the sample size would need to increase because a higher level of confidence increases the margin of error.
Given p: 10 < 7, clearly p is false and ~p is true. Also, given q: 10 < 5, clearly q is false and ~q is true.
Thus, the truth value of the conditional statement ~p → ~q is <span>T T → T.</span>
Answer:
40 black ink cartridges and 19 colored ink cartridges
Step-by-step explanation:
Let
represent the number of black printer ink cartridges sold. Let
represent the number of color printer ink cartridges sold.
Set up a system of equations:


Substitute:


⇒ 40 black ink cartridges, 19 colored ink cartridges (ans)
The question is incomplete. Here is the complete question
It was estimated that because of people switching to Metro trains about 33000 of CNG 3300 tons of diesel and 21000 tons of petrol was saved by the end of year 2007 (I) find a fraction of the quantity of diesel saved to the quantity of petrol saved (ii) find the quantity of cng to the quantity of diesel saved
Answer:
(I) 11/70
(II) 1/10
Step-by-step explanation:
Metro trains contain 330,000 tons of CNG
3300 tons of diesel was saved
21000 tons of petrol was saved at the end of 2007
(I) The fraction of the quantity of diesel saved to the quantity of petrol saved can be calculated as follows
= 3300/21000
= 11/70
(II) The fraction of the quantity of CNG saved to the quantity of diesel can be calculated as follows
= 3300/33000
= 1/10