Answer:
Step-by-step explanation:
First we find the zeroes so we don't take the integral of negative bits
4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4
![\int\limits^4_0 {4x-x^2} \, dx =[2x^2- \frac{1}{3}x^3]^4_0=(32- \frac{64}{3})-(0)= 10.6666666666](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E4_0%20%7B4x-x%5E2%7D%20%5C%2C%20dx%20%3D%5B2x%5E2-%20%5Cfrac%7B1%7D%7B3%7Dx%5E3%5D%5E4_0%3D%2832-%20%5Cfrac%7B64%7D%7B3%7D%29-%280%29%3D%20%2010.6666666666)
or aout 10 and 2/3
C is answer
Answer:
<em>908360.67 lb-ft</em>
<em></em>
Step-by-step explanation:
height of tank= 6 ft
diameter of the tank = 4 ft
density of water p = 62.4 lbs/ft
A is the cross sectional area of the tank
A = 
where r = diameter/2 = 4/2 = 2 ft
A = 3.142 x
= 12.568 ft^2
work done = force x distance through which force is moved
work = F x d
Force due to the water = pgAh
where g = acceleration due to gravity = 32.174 ft/s^2
Force = 62.4 x 32.174 x 12.568 x 6 = 151393.44 lb
work done = force x distance moved
work = 151393.44 x 6 = <em>908360.67 lb-ft</em>
40/1 = 80/2 = 120/3 = 160/4 = 200/5 = 240/6 = 280/7 = 320/8 = 360/9 = 400/10 = 440/11 = 480/12 = 520/13 = 560/14 = 600/15 = 640/16 = 680/17 = 720/18 = 760/19 = 800/20
If that helps?
Answer:
2
Step-by-step explanation:
5-3 = 2
9-9 = 0
2/0 = 2