3 years ago

I need a break down of the answer in fraction form

Mathematics

1 answer:

Flauer [41]3 years ago

6 0

Umm what do you mean?

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If you can buy 1/3 of a box of chocolates for 6 dollars, how much can you purchase for 4 dollars

zysi [14]

Answer:

2/9

Step-by-step explanation:

Since 1/3 of a box of chocolates costs 6 dollars, you can buy (4×(1/3))/6=2/9 of a box of chocolates!

7 0

4 years ago

Work out the value of <img src="https://tex.z-dn.net/?f=2%5E%7B3%7D%20%2B%205%5E%7B2%7D" id="TexFormula1" title="2^{3} + 5^{2}"

Luden [163]

Answer:

Step-by-step explanation:

2³=8

5²=25

8+25=33.

so, 2³+5²=33

4 0

3 years ago

Read 2 more answers

Solve the system by substitution: -4.5x-2y=-12.15 3.25x-y=-0.75

valina [46]

Answer:

The answer is x=0.97 while y=3.90

4 0

3 years ago

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago

Can you solve 4 .b)

saul85 [17]

Answer:

yhyhyhyh rashford gonna score a hat trick vs spurs

Step-by-step explanation:

8 0

3 years ago