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miss Akunina [59]
3 years ago
15

"Many of the transition metals (orange) can have more than one charge. The notable exceptions are zinc (always +2), silver (alwa

ys +1) and cadmium (always +2)."
If some have set/constant ionic charges do they need roman numerals?

and my follow up question,
is it always necessary to use the Roman numeral as the assigned charge of the transition metal?(if so, why? why? do roman numeral need to be added to silver etc. if they already have set charges?)
Chemistry
1 answer:
belka [17]3 years ago
7 0

Answer:Roman numerals are used in naming ionic compounds when the metal cation forms more than one ion. The metals that form more than one ion are the transition metals, although not all of them do this.

Explanation:

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Ilia_Sergeevich [38]

Answer:

A) Forward rate = 1.1934 × 10^(-4) M/min

B) I disagree with the claim

Explanation:

A) We are told that [HF] reaches a constant value of 0.0174 M at equilibrium.

The reversible reaction given to us is;

BF4-(aq) +H20(l) → BF3OH-(aq) + HF(aq)

From this, we can see that the stoichiometric ratio is 1:1:1:1

Thus, concentration of [BF4-] is now;

[BF4-] = 0.150 - 0.0174

[BF4-] = 0.1326 M

From the rate law, we are told the forward rate is kf [BF4-].

We are given Kf = 9.00 × 10^(-4) /min

Thus;

Forward rate = 9.00 × 10^(-4) /min × (0.1326M)

Forward rate = 1.1934 × 10^(-4) M/min

(B) The student claims that the initial rate of the reverse reaction is equal to zero can't be true because at equilibrium, rates for the forward and reverse reactions are usually equal.

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3 years ago
The equilibrium constant for the following equation:
Mkey [24]

From the calculation, the partial pressure of Cl2 is 1.98 atm. Option B

<h3>What is the equilibrium constant?</h3>

The term equilibrium constant refers to the value that shows us the extent to which reactants are converted into products. We know that the equilibrium constant can only be obtained by the use of the equilibrium partial pressures of each of the species.

Thus we have;

K = p PCl3 . pCl2/pPCl5

p PCl3 = partial pressure of PCl3

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pPCl5 = partial pressure of PCl5

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Substituting values;

1.05 =  0.463 *  pCl2/0.875

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The laser pulse in this question has a wavelength of \lambda=524 nm=525\times 10^{-9}m. To solve this problem, we first have to calculate the energy of a single photon in the laser pulse. The equation for calculating the energy of a single photon of an electromagnetic wave is E=\frac{hc}{\lambda} where c is the speed of light, h is planks constant and \lambda is the wave length of the photons.

For this problem, c=3.0\times 10^8m/s, h=6.63\times10^{-34}J.s and \lambda=525\times 10^{-9}m. We use these values to calculate the energy of the photon as shown below,

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Now that we know the energy for a single photon, we will divide the total energy given by the energy of one photon to get the number of photons in the pulse. The number of photons n is calculated as shown below,

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