$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\(\stackrel{x_1}{-2}~,~\stackrel{y_1}{2})\qquad(\stackrel{x_2}{4}~,~\stackrel{y_2}{-6})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\d=\sqrt{[4-(-2)]^2+[-6-2]^2}\implies d=\sqrt{(4+2)^2+(-6-2)^2}\\\\\\d=\sqrt{6^2+(-8)^2}\implies d=\sqrt{100}\implies d=10$

4 0

3 years ago

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PLEASE HEEEEEEEEELLLLLLLLLPPPPPPP WILLING TO GIVE BRAINLIEST.

hoa [83]

I hope this helps, If there are 5 cups of flour, then there will be 7 and 1/2 cups of sugar:)

4 0

3 years ago

1. Emma used elimination to solve this system of linear equations. 3x + 5y = -17 2x + 4y = 6 Which equation did Emma have after

Gwar [14]

Answer:

2y=52

Step-by-step explanation:

1st equation *(-3) and 2nd *(2)

-6x-10y=34

6x+12y=18

eliminate -6x and 6x

add both equations

2y=52

6 0

3 years ago

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Line CD contains points C(7, 4) and D(6, 1). Line JK is parallel to line CD. Which two points lie on line JK?

Andru [333]

From 6,1 to 7,4
We can determine the slope of the line
rise/run
3/1=3

Now we know the slope of the line, a line parallel to it must obtain the same slope, therefore, I tried to see if the increase in y is three times the increase in x
I found the true pair to be A

(-4,1) and (-2,7)

6 0

3 years ago

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