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Ronch [10]
3 years ago
15

Jerry goes to a theme park to ride the roller coasters. The theme park charges an entry fee in addition to a fee for each roller

coaster ride. The table below represents the total price for two different numbers of roller coaster rides.

Mathematics
2 answers:
Otrada [13]3 years ago
6 0
The first roller coaster is 35 for 5 which means $7 for 1 ride
the second roller coaster is 59 for 11 which means 59 divided by 11 get 5.36
5.36 times 11 = 58.96 probrably a combo so it is estimated upward

Ray Of Light [21]3 years ago
3 0

Answer:

Price for entry fee is $15, and price for each ride is $4.

Step-by-step explanation:

We have to tell how much it is for the entry fee and how much for each ride?

Let the price for roller coaster ride be = x

Let the price for the entry fee be = y

Looking at the table, we can form equations.

5x+y=35   ...(1)

11x+y=59    ....(2)

Now we will solve these. Subtracting equation 1 from equation 2.

6x=24

x = 4

Substituting value of x in equation 1

5(4)+y=35

20+y=35

y=35-20=15

Hence, y = 15

So, entry fee is $15

And price of per ride is $4

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How does a digit in the ten thousandths place compare to a digit in the thousands place
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3 years ago
Find<br>a,b<br>such<br>that 7.2, a, b, 3 are in A.P.​
leonid [27]

Answer:

  • The value of a = 5.8
  • The value of b = 4.4

Step-by-step explanation:

Given

7.2, a, b, 3 are in A.P

2a = 7.2+b

b = 2a - 7.2

as

a, b, 3 are also in A.P

2b\:=\:a\:+\:3

Putting b = 2a - 7.2

2\left(2a-7.2\right)=a+3

4a-14.4=a+3

\mathrm{Add\:}14.4\mathrm{\:to\:both\:sides}

4a-14.4+14.4=a+3+14.4

4a=a+17.4

4a-a=a+17.4-a

3a=17.4

\mathrm{Divide\:both\:sides\:by\:}3

\frac{3a}{3}=\frac{17.4}{3}

a=5.8

Now, plugging a=5.8 in b = 2a - 7.2

b=2\left(5.8\right)-7.2

b=2\cdot \:5.8-7.2

b=11.6-7.2

b=4.4

Therefore,

  • The value of a = 5.8
  • The value of b = 4.4
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3 years ago
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nexus9112 [7]

Answer:

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Step-by-step explanation:

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Just take it in co-ordinate pairs

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Slope:-

\\ \sf\longmapsto m=\dfrac{40-60}{41-58}

\\ \sf\longmapsto m=\dfrac{-20}{-17}

\\ \sf\longmapsto m=\dfrac{20}{17}

\\ \sf\longmapsto m\approx 1.2

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\\ \sf\longmapsto y-60=1.2(x-58)

\\ \sf\longmapsto y-60=1.2x-69.6

\\ \sf\longmapsto 1.2x-y-9.6=0

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\\ \sf\longmapsto y=1.2x-9.6

Graph attached

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