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mixas84 [53]
3 years ago
11

A peregrine falcon can fly 322 kilometers per hour. How many meters per hour can the falcon fly

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
3 0
<span>322,000 meters. Because there is 1,000 meters in a kilometer.</span>
You might be interested in
Which equation is y = â€""6x2 3x 2 rewritten in vertex form?.
Ber [7]

The vertex form needed is :

-6(x-0.25)^2 +2.375

Given the equation:

-6x^2 + 3x + 2\\

The vertex form of f(x) = ax^2 + b(x) + c is given by:

f(x) = a(x-h)^2 + k

Here, (h,k) is the vertex of the parabola equation given.

Conversion will go like this:

-6x^2 + 3x + 2\\= -6(x^2 - 0.5x) + 2\\= -6(x^2 -0.5x + 0.0625 - 0.0625) + 2\\= -6(x^2 -0.5x + 0.0625) + 2 +0.375\\= -6(x-0.25)^2 + 2.375\\\\

This is the resultant vertex form.

Thus the vertex form needed is :

-6(x-0.25)^2 +2.375

Learn more here:

brainly.com/question/15165354

6 0
2 years ago
8 and 1/5 + 4 and 2/5=?
Leviafan [203]
12 and 3/5 hope this helped
4 0
3 years ago
Any help is appreciated:)<br><br>God blast it the photo didn’t load
mart [117]

... what is the question lol

6 0
3 years ago
Which expression is equal to 5/9
lesya [120]
Hello, There are endless expressions. Since, you multiply this fraction by a costant k / k

If k = 2

Then,

(5/9) = ( 5/9) × ( k / k)

= (5/9) × ( 2/2)

= (5 × 2 / 9×2)

= 10 / 18
________________

The only restriction for k is zero and the infinite. Because there is no "0/0" and "infinito/ infinito" at math.


3 0
3 years ago
Find the equation of the tangent line and normal line to the curve y=(6+4x)2 at the point (6,900). Write the equations of the li
Ksenya-84 [330]

Answer:

Equation of the tangent to the curve

y = 240x - 215994

Equation of the normal

y = (-1/240)x + 9.75 = - 0.00417x + 9.75

Step-by-step explanation:

y = (6 + 4x)² = 36 + 48x + 16x² = 16x² + 48x + 36

dy/dx = 32x + 48

At the point (6,900),

dy/dx = 32(6) + 48 = 240

Equation of the tangent at point (a,b) is

(y - b) = m(x - a)

a = 6, b = 900, m = 240

y - 6 = 240(x - 900)

In the y = mx + b form,

y - 6 = 240x - 216000

y = 240x - 215994

The slope of the normal line = -(1/slope of the tangent line) (since they're both perpenducular to each other)

Slope of the normal line = -1/240

Equation of normal

y - 6 = (-1/240)(x - 900)

y - 6 = (-x/240) + 3.75

y = (-1/240)x + 9.75

y = - 0.00417x + 9.75

8 0
3 years ago
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