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kari74 [83]
4 years ago
9

What are not natural disasters

Chemistry
2 answers:
borishaifa [10]4 years ago
6 0

Answer:

Std's are not natural disasters.

Explanation:

This is because std's were created in a lab by people meaning it's not natural at all.

snow_tiger [21]4 years ago
4 0

Answer:

Explanation:  Natural disasters are disasters that dont happen because of nature. A person does it.

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A 2.00L canister is charged with C3H8 and O2 to a total pressure of 1.50 atm at 0.0 degrees C The mole fraction of C3H8 in the c
tankabanditka [31]

Answer:

c

Explanation:

6 0
3 years ago
3. Joseph took some sodium hydroxide solution in a petri dish and dipped a red litmus paper into it. The red litmus paper turned
olasank [31]

Answer:

Blue Litmus will change into red if it is added in sodium hydroxide

Explanation:

7 0
3 years ago
What happens to the particles as you increase the oven’s temperature
vekshin1
The particles move faster because heat causes the atoms to speed up and move farther from each other.
3 0
4 years ago
What is the ph of 0.51 m ca(ch3coo)2 solution?
Sidana [21]

Answer : The pH of calcium acetate solution will be 9.38.


Explanation : When calcium acetate dissocates completely in solution to form Calcium(+2) ions and two acetate ions, this gives the acetate ion concentration as (2 X 0.51 M) = 1.02 M

Acetate ion then hydrolyzes as follows;


C_{2}H_{3}O_{2}^{-}  + HOH  HC_{2}H_{2}O_{2} + OH^{-}:

Now, Kb will be = [HC_{2}H_{2}O_{2}]  [OH^{-}] / [C_{2}H_{3}O_{2}^{-}]


= Kw / Ka


= 1 x 10^{-14} / 1.8 x 10^{-5} = 5.6 × 10^{-10}

[OH^{-}] = 2.4 × 10^{-5}


Now, we know , pOH = -log [OH^{-}] = 4.62


So, the pH = 14 - pOH = 14 - 4.62 = 9.38

8 0
3 years ago
In the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O, an equivalence point occurs when 32.23 mL of 0.2423 M NaOH is added to a 37.
stepladder [879]
The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applies to an acid-base titration.
            moles NaOH = c · V = 0.2423 mmol/mL · 32.23 mL = 7.809329 mmol
            moles H2SO4 = 7.809329 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.9046645 mmol
Hence
            [H2SO4]= n/V = 3.9046645 mmol / 37.21 mL = 0.1049 M
The answer to this question is  [H2SO4] = 0.1049 M
5 0
4 years ago
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