18+2(4-1) equation please help!

Which logarithmic equation is equivalent to 2^5=32?

kolbaska11 [484]

Answer: $5=log_{2}(32)$

Step-by-step explanation:

1. By definition, you have if $y=b^{x}$ , then $x=log_{b}(y)$

2. Keeping this on mind, you must follow the proccedure shown below:

- You have that:

$2^{5}=32$

Where:

$x=5\\y=32\\b=2$

- Substitute values into $x=log_{b}(y)$ . Then, you obtain:

$5=log_{2}(32)$

6 0

2 years ago

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Look at triangles TUV and T'U'V'.Which best explains the transformation of triangle TUV to form triangle T'U'V'?

Iteru [2.4K]

Answer:

The answer is D or Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle T"U"V" . I just took the test and I hope I helped : )

Step-by-step explanation:

6 0

2 years ago

Given that g(x) = 2x ^ 2 - 2x + 8 , find each of the following. a) g(0) b) g(- 2) C) g(3) d) g(- x) e) g(1 - t)

raketka [301]

Answer:

$g(-2)=20$

Step-by-step explanation:

Given $g(x)=2x^2-2x+8$ , substitute what is in the parentheses for $x$ to find an output.

For $g(-2)$ , the term $-2$ is in the parentheses. Thus, substitute $x=-2$ into $2x^2-2x+8$ to find $g(-2)$ :

$g(-2)=2(-2)^2-2(-2)+8,\\g(-2)=2\cdot 4+4+8,\\g(-2)=8+4+8,\\g(-2)=\boxed{20}$

5 0

2 years ago

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The three sides of a triangle are n, 3n+3, and 2n+11. If the perimeter of the triangle is 50 inches, what is the length of each

mylen [45]

Answer:

6, 21, and 23 inches

Step-by-step explanation:

The perimeter of a triangle is equal to the sum of all side lengths in that triangle. We're given the perimeter as 50 inches, and the side lengths as n, 3n + 3, and 2n + 11.