18+2(4-1) equation please help!
1 answer:
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Answer: C
the mean and the median
Step-by-step explanation:
From the attached table,
The range of group A = 5 - 0 = 5
The range of group B = 4 - 1 = 3
Difference in range is not equal to $1
The mode of A = 1
The mode of B = 3
Difference in mode is not equal to $1
The median of A = (1 + 2)/2 = 1.5
The median of B = 3
Difference = 3 - 1.5 = $1.5
The mean of A = 16/15 = 1.07
The mean of B = 40/15 = 2.67
The difference = $1.6
From the above analysis, we can therefore conclude that non of the measures are $1 greater for Group B than for Group A
The best option among the options is
the mean and the median
