KE at 16m/s
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Givens
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m = 575 kg
v = 16 m/s
Formula
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KE = 1/2 m* v^2
KE = 1/2 575 * 16^2
KE = 73600
Second Question
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m = 575
v = 32 m/s
KE = 1/2 mv^2
KE = 1/2 575 * 32^2
KE = 294400
Third Question
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Ke2 = KE1 * k where k is the number of times greater the second is than the first.
294400 = k * 73600
k = 294400 / 73600
k = 4 So the KE of the second condition is 4 times the first.
Answer:C) light rays reflect and remain concentrated in a bundle upon leaving the water's surface.
Explanation:
) light rays reflect and remain concentrated in a bundle upon leaving the water's surface.
Balancing equations??? This shi tough
Answer:
To distinguish results based on the only two variables of
awareness.
Explanation:
Answer:
Explanation:
For first overtone
Standing waves will be formed lengthwise and breadth-wise in the enclosures having dimension of .75m x 1.5 m
A ) For the formation of lowest two frequencies formed by standing waves along the breadth , fundamental note and first overtone may be considered.
For fundamental note ,
the condition is
wave length λ = 2L = 2 x 0.75 m
λ = 1.5 m
frequency n = v / λ
= 343 / 1.5
= 229 Hz approx
For first overtone
λ = L = 0.75m
frequency n = v / λ
n = 343 / 0.75
= 457 Hz approx
B)
For the formation of lowest two frequencies formed by standing waves along the length , fundamental note and first overtone may be considered.
For fundamental note ,
the condition is
wave length λ = 2L = 2 x 1.5 m
λ = 3 m
frequency n = v / λ
= 343 / 3
= 114 Hz approx
frequency n = v / λ
n = 343 / 1.5
= 229 Hz approx