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Ratling [72]
3 years ago
13

A car is pushed and travels 12 m. The same car is then pushed and it travels 15m. What

Physics
1 answer:
Butoxors [25]3 years ago
6 0
<h3>2 Answers: Choice A, Choice B</h3><h3>Mass was decreased</h3><h3>Force was increased</h3>

=========================================

Explanation:

If the force is kept the same, but the mass was decreased, then the car will travel further. The less mass an object has, the less inertia it has. Inertia is the tendency for the object to stay at rest if it's initially at rest (or the tendency for the object to stay in motion if already in motion).

If the mass is kept the same, but the force was increased, then the object will travel further than before. The same idea applies as discussed in the last paragraph.

------

If the force was decreased and mass kept the same, then there is less push, which results in the object traveling a shorter distance. If the mass is increased but the force kept the same, then the object moves a shorter distance because there's more inertia to overcome. There are more particles needed to be moved and they resist motion if at rest.

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I NEED HELP ASAP!!! 100 points if you answer these 7 questions:
netineya [11]

Answer:

#1. B. Alfred Wegener

#2. C. Volcanic activity at the ocean bottom.

#3. B, C. Continental, Sea floor (oceanic).

#4. B. Folding

#5. B. Tectonics

#6. C. Point underground where the earthquake starts

#7. C. Flood waters carrying away soil

Explanation:

#1. Alfred Lothar Wegener was a German polar researcher, geophysicist and meteorologist. During his lifetime he was primarily known for his achievements in meteorology and as a pioneer of polar research, and is also known as the father of plate tectonics.

#2. The most prominent feature of ocean topography discovered in the 1960s was: Volcanic activity at the ocean bottom. The continents have always been in their current positions.

#3. Tectonic plates are composed of oceanic lithosphere and thicker continental lithosphere, each topped by its own kind of crust. The two types of tectonic plates are continental and oceanic tectonic plates.

#4. Tremendous pushing forces exerted by two of Earth's plates moving together squeezed rock layers from opposite sides. This caused the rock layers to buckle and fold, forming folded mountains. Folded mountains are mountains formed by the folding of rock layers caused by compression forces.

#5. Plate tectonics is the scientific theory explaining the movement of the earth's crust. It is widely accepted by scientists today. Recall that both continental landmasses and the ocean floor are part of the earth's crust, and that the crust is broken into individual pieces called tectonic plates.

#6. The hypocenter is the point within the earth where an earthquake rupture starts. The epicenter is the point directly above it at the surface of the Earth. Also commonly termed the focus. See also epicenter.

#7. This process is known as erosion. In earth science, erosion is the action of surface processes that removes soil, rock, or dissolved material from one location on the Earth's crust, and then transports it to another location.

Hope this helps!

Have a nice day!

If you find my answer helpful

<em>Pls consider marking my answer as </em><em>Brainliest</em><em>! It would mean a lot!</em>

3 0
3 years ago
A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east​
elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: 56.31^o

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\

Now we can find the value of the angle by using the arctan function:

tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o

6 0
3 years ago
Find the magnitude of pressure in Pascal of 150N that acts normally on area. Of 0.25m2
s2008m [1.1K]

Pressure = force/ area

= 150N/ 0.25m^2

= 600Pa

5 0
3 years ago
When you walk with a cup of coffee (diameter5 cm) at just the
vladimir1956 [14]

Answer:

10 cm/sec

Explanation:

using formula velocity = frequency * wave length

where: f=1/T

1/1=1

so frequency will be 1HZ ( due to 1 oscillation in 1 sec)

wave length will be 10 cm because while sloshing cup hold (1/2) half full length.

velocity = 1*10 = 10cm/sec.

velocity = 10 cm/sec

4 0
3 years ago
Interactive LearningWare 4.1 reviews the approach taken in problems such as this one. A 1800-kg car is traveling with a speed of
Lubov Fominskaja [6]

Answer:

F= 4788 N

Explanation:

Because the car moves with uniformly accelerated movement we apply the following formula:

vf²=v₀²+2*a*d Formula (1)

Where:  

d:displacement in meters (m)  

v₀: initial speed in m/s    

vf: final speed in m/s  

a: acceleration in m/s²

Data

d=36.9 m

v₀=14.0 m/s m/s    

vf= 0  

Calculating of the acceleration of the car

We replace dta in the formula (1)

vf²=v₀²+2*a*d

(0)²=(14)²+2*a*(36.9)

-(14)²= (73.8) *a

a= - (196) /  (73.8)

a= - 2.66 m/s²

Newton's second law of the car in direction  horizontal (x):

∑Fx = m*ax Formula (2)

∑F : algebraic sum of the forces in direction x-axis (N)

m : mass (kg)

a : acceleration  (m/s²)

Data

m=1800 Fkg

a= - 2.66 m/s²

Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :

We replace data in the formula (2)

-F= (1800 kg) * ( -2.66 m/s² )

F= 4788 N

6 0
3 years ago
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