Answer:
see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas
Explanation:
We will propose this exercise using Archimedes' principle, which establishes that the thrust on a body is equal to the volume of the desalted liquid.
B = ρ g V
The weight of a submerged body is the net force between the weight and the thrust
F_net = W - B
we can write the weight as a function of the density
ρ_body = m / V
m = ρ_body V
W = mg
W = ρ _body g V
we substitute
F_net= ( ρ_body - ρ _fluid) g V
In general this force is directed downwards, we can call this value the apparent weight of the body. This is the weight of the submerged body.
W_aparente = ( ρ_body - ρ _fluid) g V
If some air bubbles formed in this body, the net force of these bubbles is
F_net ’= #_bubbles ( ρ_fluido - ρ_air) g V’
this force is directed upwards
whereby the measured force is
F = W_aparente - F_air
As we can see from this analysis, the apparent weight of the body is lower due to the push created by the air brujuleas
Charge = 0.2 Ah is the correct answer...
Answer:
D. You will feel the same weight as you do on Earth
Explanation:
In free space, she is suppose to be weightless.
Free fall can be described as body in motion where the body is under the effect of acceleration due to gravity only and no other acceleration..
Since I am accelerating away from her at an acceleration of 1g
Then,
F=ma, where a=g
Then F=mg
Since my weight on earth is W=mg
This is equals to my weight in the spaceship, then I will feel the same weights as I do on earth.
Yes. It r<span>efers to any of the temperatures assigned to a number of reproducible equilibrium states on the International Practical Temperature Scale</span><span>
In short, Your Answer would be "True"
Hope this helps!</span>
