Answer: The correct answers are (A) and (C).
Explanation:
The expression from electrostatic force is as follows;

Here, F is the electrostatic force, k is constant, r is the distance between the charges and
are the charges.
The electrostatic force follows inverse square law. It is inversely proportional to the square of the distance between the charges. It is directly proportional to the product of the charges.
Like charges repel each other. There is a force of electrostatic repulsion between the like charges. Unlike charges attract each other. There is a force of electrostatic attraction between unlike charges.
The charges are induced on the neutral object when it is placed nearby the charged object without actually touching it.
Therefore, the true statements from the given options are as follows;
Like charges repel.
Unlike charges attract.
Answer:
123.30 m
Explanation:
Given
Speed, u = 22 m/s
acceleration, a = 1.40 m/s²
time, t = 7.30 s
From equation of motion,
v = u + at
where,
v is the final velocity
u is the initial velocity
a is the acceleration
t is time
V = at + U
using equation v - u = at to get line equation for the graph of the motion of the train on the incline plane
where m is the slope
Comparing equation (1) and (2)

a = m
Since the train slows down with a constant acceleration of magnitude 1.40 m/s² when going up the incline plane. This implies the train is decelerating. Therefore, the train is experiencing negative acceleration.
a = - 1.40 m/s²
Sunstituting a = - 1.40 m/s² and u = 22 m/s


The speed of the train at 7.30 s is 11.78 m/s.
The distance traveled after 7.30 sec on the incline is the area cover on the incline under the specific interval.
Area of triangle + Area of rectangle
![[\frac{1}{2} * (22 - 11.78) * (7.30)] + [(11.78 - 0) * (7.30)]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%20%2A%20%2822%20-%2011.78%29%20%2A%20%287.30%29%5D%20%20%2B%20%5B%2811.78%20-%200%29%20%2A%20%287.30%29%5D)
= 37.303 + 85.994
= 123. 297 m
≈ 123. 30 m
Explanation:
They will repel, thus made of electrical conductor.
Answer:
![(a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=%28a%29%5C%20F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)

Explanation:
Given
---- Altitude of container in Denver
-- Surface Area of the container lid
--- Air pressure in Denver
--- Air pressure in New Orleans
<em>See comment for complete question</em>
Solving (a): The expression for 
Force is calculated as:

The force in New Orleans is:

Since the inside pressure is half the pressure at sea level, then:

Where
--- Standard Pressure
Recall that:

This gives:
![F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)
Solving (b): The value of 
In (a), we have:
![F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)
Where



So, we have:
![F_{No} = [100250 - \frac{101000}{2}] * 0.0155](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5B100250%20-%20%5Cfrac%7B101000%7D%7B2%7D%5D%20%2A%200.0155)
![F_{No} = [100250 - 50500] * 0.0155](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5B100250%20-%2050500%5D%20%2A%200.0155)

