Answer:
Explanation:
We are given that
Initial kinetic energy of an electron=K
Distance=d
Final velocity=v=0
Charge,q=-1e
We have to find the magnitude of electric field.
Work done=
Using the formula
Work done=
Using work energy theorem
Work done=Final K.E-Initial K.E=0-K
Work done=-K
Substitute the values
-K=-eEd
K=eEd
Hence, the magnitude of the electric field=
Answer:
Approximately (assuming that the projectile was launched at angle of
above the horizon.)
Explanation:
Initial vertical component of velocity:
.
The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing is the same as the altitude
at which this projectile was launched:
.
Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is (upwards,) the vertical velocity right before landing would be
(downwards.) The change in vertical velocity is:
.
Since there is no drag on this projectile, the vertical acceleration of this projectile would be . In other words,
.
Hence, the time it takes to achieve a (vertical) velocity change of would be:
.
Hence, this projectile would be in the air for approximately .