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riadik2000 [5.3K]
3 years ago
10

Al is floating freely in her spacecraft, and you are accelerating away from her with an acceleration of 1g. 5) How will you feel

in your spacecraft? A) You will be floating weightlessly. B) You will feel weight, but less than on Earth. C) You will feel weight, but more than on Earth. D) You will feel the same weight as you do on Earth. E) You will feel yourself pressed against the back of your spaceship with great force, making it difficult to move.
Physics
1 answer:
wariber [46]3 years ago
5 0

Answer:

D. You will feel the same weight as you do on Earth

Explanation:

In free space, she is suppose to be weightless.

Free fall can be described as body in motion where the body is under the effect of acceleration due to gravity only and no other acceleration..

Since I am accelerating away from her at an acceleration of 1g

Then,

F=ma, where a=g

Then F=mg

Since my weight on earth is W=mg

This is equals to my weight in the spaceship, then I will feel the same weights as I do on earth.

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By what factor will the Electrostatic Force between two charged objects change when the amount of charge on both objects doubles
Mademuasel [1]

Answer:

F' = (4/9)F

Explanation:

The electrostatic force between two charged objects is given by Coulomb's Law:

F = kq₁q₂/r²   -------------------- equation (1)

where,

F = Electrostatic Force

k = Coulomb's Constant

q₁ = magnitude of first charge

q₂ = magnitude of second charge

r = distance between charges

Now, when the charges and distance altered as follows:

q₁' = 2q₁

q₂' = 2q₂

r' = 3r

Then,

F' = kq₁'q₂'/r'²

F' = k(2q₁)(2q₂)/(3r)²

F' = (4/9)kq₁q₂/r²

using equation (1):

<u>F' = (4/9)F</u>

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2 years ago
.A coin rolls off the edge of a table. The coin
geniusboy [140]

Answer:

Apply the following formulae horizontally And get A value for time

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s  = ut +  \frac{1}{2}a {t}^{2}   \\ 0.8 = 1.7 \times t \\  \frac{0.8}{1.7}  = t \\ t = 0.47s

and then to find the height apply the same above equation vertically...remember vertical initial velocity is zero

s = ut +  \frac{1}{2} a {t}^{2}  \\ s =  \frac{1}{2}  \times 10 \times (0.47) ^{2}  \\ s = 1.1045m

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A 2.4-kg ball falling vertically hits the floor with a speed of 2.5 m/s and rebounds with a speed of 1.5 m/s. What is the magnit
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Answer:

9.6 Ns

Explanation:

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I = m(v-u).................. Equation 1

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Given: m = 2.4 kg, v = 2.5 m/s, u = -1.5 m/s (rebounds)

Substitute into equation 1

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