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riadik2000 [5.3K]
3 years ago
10

Al is floating freely in her spacecraft, and you are accelerating away from her with an acceleration of 1g. 5) How will you feel

in your spacecraft? A) You will be floating weightlessly. B) You will feel weight, but less than on Earth. C) You will feel weight, but more than on Earth. D) You will feel the same weight as you do on Earth. E) You will feel yourself pressed against the back of your spaceship with great force, making it difficult to move.
Physics
1 answer:
wariber [46]3 years ago
5 0

Answer:

D. You will feel the same weight as you do on Earth

Explanation:

In free space, she is suppose to be weightless.

Free fall can be described as body in motion where the body is under the effect of acceleration due to gravity only and no other acceleration..

Since I am accelerating away from her at an acceleration of 1g

Then,

F=ma, where a=g

Then F=mg

Since my weight on earth is W=mg

This is equals to my weight in the spaceship, then I will feel the same weights as I do on earth.

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stiv31 [10]

Abstract. Abstract is defined as an idea or plan but no actions are done

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6 0
3 years ago
Read 2 more answers
A car slows down uniformly from a speed of 30.0 m/s to rest in 7.20 s
Ede4ka [16]

When acceleration is constant, the average velocity is given by

\bar v=\dfrac{v+v_0}2

where v and v_0 are the final and initial velocities, respectively. By definition, we also have that the average velocity is given by

\bar v=\dfrac{\Delta x}{\Delta t}=\dfrac{x-x_0}{t-t_0}

where x,x_0 are the final/initial displacements, and t,t_0 are the final/initial times, respectively.

Take the car's starting position to be at t_0=0\,\mathrm s. Then

\dfrac{v+v_0}2=\dfrac{x-x_0}t\implies x=x_0+\dfrac12(v+v_0)t

So we have

x=0\,\mathrm m+\dfrac12\left(0\,\dfrac{\mathrm m}{\mathrm s}+30.0\,\dfrac{\mathrm m}{\mathrm s}\right)(7.20\,\mathrm s)=108\,\mathrm m

You also could have first found the acceleration using the equation

v=v_0+at

then solve for x via

x=x_0+v_0t+\dfrac12at^2

but that would have involved a bit more work, and it turns out we didn't need to know the precise value of a anyway.

7 0
3 years ago
Which of the following is a theory stating that one plate is forced beneath another plate?
morpeh [17]

Answer:

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7 0
3 years ago
You want to make a ride so you do not want to exceed 1.1g’s, if the radius of the turns are 10m, then what is the maximum speed
Citrus2011 [14]

The maximum speed is 10.4 m/s

Explanation:

For a body in uniform circular motion, the centripetal acceleration is given by:

a=\frac{v^2}{r}

where

v is the linear speed

r is the radius of the circular path

In this problem, we have the following data:

- The maximum centripetal acceleration must be

a=1.1 g

where g=9.8 m/s^2 is the acceleration of gravity. Substituting,

a=(1.1)(9.8)=10.8 m/s^2

- The radius of the turn is

r = 10 m

Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:

v=\sqrt{ar}=\sqrt{(10.8)(10)}=10.4 m/s

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

8 0
3 years ago
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