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3 years ago

A rectangle has a length of 12 cm and a diagonal of 13 cm. What is the width? *Hint: Draw a picture

Mathematics

1 answer:

Hitman42 [59]3 years ago

3 0

Answer:

width = 5cm

Step-by-step explanation:

hope it helps

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Please answer this :(

mojhsa [17]

Answer:

68.9°

Step-by-step explanation:

Using Sine rule

x/sin X = y/sin Y

4.5/sin X = 4/sin 56

sin X × 4 = 4.5 × sin 56

sin X = 4.5 × sin 56/4

X = arc sin (4.5 × sin 56/4)

X = 68.85449°

Approximately = 68.9°

4 0

2 years ago

Milo has 2 hours of free time. He spends 2/4 of an hour with his dog. He spends 3/4 of an hour drawing. What fraction of an hour

blagie [28]

Answer: 3/4 of an hour left.

Step-by-step explanation:

Step 1: 2 hours = 4/4 +4/4

Step 2: 4/4 - 2/4 = 2/4

Step 3: 4/4 - 3/4 = 1/4

Step 4: 2/4 + 1/4= 3/4

3 0

3 years ago

Please help me!

yan [13]

Answer:

Step-by-step explanation:

A = Area of First Rectangle 

B = Area of Second Rectangle 

w = Width

12(w)=320+B (1st Equation)

8(w) = B (2nd Equation)

w=B/8 (Plug this value of w into the first equation)

12B/8 = 320 +B (you get this)

12B= 2560 + 8B (Simplify)

4B = 2560

B =640 plug this value into the 2nd equation

8(w) = 640

w = 80

To Test This

12x80 = 960

8x80 = 640

<h3>960 - 640 = 320 Therefore the answer is correct the width is 80</h3>

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5 0

2 years ago

A distance of 150 km was covered by a motorcyclist traveling at an average speed of 75 km/h, by a bus at 60 km/h, a truck at 50

Maurinko [17]

Motorcyclist: 2 hours
Bus: 2.5 hours
Truck: 3 hours
Bicyclist: 7.5 hours

7 0

3 years ago

Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte

Tpy6a [65]

Answer:

$3\frac{13}{20}=3.65$ kg.

Step-by-step explanation:

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are $2\frac{1}{4}$ kg.

To find the amount of strawberries picked by Sheldon in the afternoon we will add $2\frac{1}{4}$ and $1\frac{2}{5}$ :

$S= 2\frac{1}{4}+1\frac{2}{5}$

Upon converting our given mixed fractions into improper fraction we will get,

$S= \frac{9}{4}+\frac{7}{5}$

Now let us have a common denominator.

$S=\frac{9*5}{4*5}+\frac{7*4}{5*4}$

$S=\frac{45}{20}+\frac{28}{20}$

$S=\frac{45+28}{20}$

$S=\frac{73}{20}$

$S=3\frac{13}{20}$

$S=3.65$

Therefore, Sheldon picked $3\frac{13}{20}=3.65$ kg of strawberries in the afternoon.

3 0

3 years ago