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gizmo_the_mogwai [7]
3 years ago
7

Get really big brain for this

Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

what if he just doesnt say it at all. lol that would save some hard thinking.

Step-by-step explanation:

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If f(x)=x^2-2x-8 and g(x)=1/4x-1, for which value of x is f(x)=g(x)?
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Answer:

The answer is 4

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Solve the equation on the interval [0,2π]
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\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0&#10;\\\\\\&#10;~~~~~~~~~~~~\textit{quadratic formula}&#10;\\\\&#10;\begin{array}{lcccl}&#10;& 8 sin^4& -6 sin^2(x)& +1\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array} &#10;\qquad \qquad &#10;sin(x)= \cfrac{ -  b \pm \sqrt {  b^2 -4 a c}}{2 a}&#10;\\\\\\&#10;sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}&#10;\\\\\\&#10;sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=&#10;\begin{cases}&#10;\frac{1}{2}\\\\&#10;\frac{1}{4}&#10;\end{cases}

\bf \measuredangle x=&#10;\begin{cases}&#10;sin^{-1}\left( \frac{1}{2} \right)&#10;sin^{-1}\left( \frac{1}{4} \right)&#10;\end{cases}\implies \measuredangle x=&#10;\begin{cases}&#10;\frac{\pi }{6}~,~\frac{5\pi }{6}\\&#10;----------\\&#10;\approx~0.252680~radians\\&#10;\qquad or\\&#10;\approx~14.47751~de grees\\&#10;----------\\&#10;\pi -0.252680\\&#10;\approx 2.88891~radians\\&#10;\qquad or\\&#10;180-14.47751\\&#10;\approx 165.52249~de grees&#10;\end{cases}
3 0
3 years ago
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