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scZoUnD [109]
3 years ago
14

An aspirin tablet weighing 0.400 g has been analyzed and contains 68.2% acetylsalicylic acid (ASA) (180.16 g/mol) by mass. A stu

dent dissolved the tablet in hot NaOH and the cooled solution was diluted with deionized water to the mark in a 250 mL volumetric flask. Exactly 3.00 mL of the solution was pipetted into a 100 mL volumetric flask and diluted to the mark with FeCl3 solution. Calculate the concentration of ASA in the diluted solution.
Chemistry
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

0.00018M

Explanation:

Mass of the aspirin tablet =0.4g.

% by mass of ASA=68.2

mass of in the tablet=68.2/100×0.4g

=0.2748g

mass conc of ASA=mass of ASA/Volume of diluent(250ml)

=0.2748/0.25

=1.0992g/dm3

molar conc=mass conc/molar mass

=1.0992/180.16

=0.006M

Conc of the stock solution C1=0.006M

Initial volume for making the diluted solution(V1)=3ml

final volume of the diluted solution=100ml

from dilution principle

no of mole=conc × volume

initial conc(C1)×initial volume(V1)=final conc(C2)×final volume(V2)

C2=0.006M×3ml/100ml

=0.00018M

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How much 10.0 M HNO3 must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the p
sladkih [1.3K]
Initial moles of CH₃COOH = 1.00 x 0.0100 = 0.0100 mol

Initial moles of CH₃COONa = 1.00 x 0.100 = 0.100 mol


Let a be the volume of HNO₃ that must be added

Moles of HNO₃ added = a/1000 x 10.0 = 0.01a mol

CH₃COONa + HNO₃ => CH₃COOH + NaNO₃


Moles of CH₃COOH = 0.0100 + 0.01a

Moles of CH₃COONa = 0.100 - 0.01a


pH = pKa + log([CH₃COONa]/[CH₃COOH])

= pKa + log(moles of CH₃COONa/moles of CH₃COOH)


5.05 = 4.75 + log((0.100 - 0.01a)/(0.0100 + 0.01a))

log((0.100 - 0.01a)/(0.0100 + 0.01a)) = 0.3

(0.100 - 0.01a)/(0.0100 + 0.01a) = 10^0.3 = 2.0

0.03 a = 0.08

a = 2.67


<span>Volume of HNO3 = a = </span>2.13 mL
8 0
3 years ago
How many moles of Gold (III) sulfide must decompose to produce 4.32 moles of gold
sertanlavr [38]

Answer:

2.16 moles of Au₂S₃  are decomposed.

Explanation:

Given data:

Number of moles of gold (III) sulfide decomposed = ?

Number of moles of gold metal formed = 4.32 mol

Solution:

Chemical equation:

Au₂S₃      →       2Au + 3S

Now we will compare the moles of Au₂S₃ with  gold metal.

                            Au             :           Au₂S₃  

                             2              :                1

                            4.32         :             1/2×4.32 = 2.16    

2.16 moles of Au₂S₃  are decomposed.    

                           

3 0
2 years ago
a student combined 45.3 ml of a 0.549 m calcium nitrate ca(no₃)₂ solution with 85.55 ml of a 1.321 m ca(no₃)₂ solution. calculat
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When we combine the provided amounts of 0.549 M calcium nitrate Ca(NO3)2 solution and 1.321 M Ca(NO3)2 solution, the ultimate concentration of Ca(NO3)2 is 8.76 M.

<h3>What is molar concentration?</h3>

The amount of a solute present in one unit of a solution is known as its molar concentration. Mol/L, mol/dm3, or mol/m3 are its units. Molar concentration, also referred to as molarity, can be expressed with the letter M, or molar.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.

The ratio of the solute to solution amounts is known as concentration. A solute's molarity per liter of solution is measured using the unit of concentration.

To learn more about molarity here-

brainly.com/question/14469428

#SPJ4

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Answer:

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Explanation:

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Answer:

A hypothesis is either a suggested explanation for an observable phenomenon, or a reasoned prediction of a possible causal correlation among multiple phenomena. In science, a theory is a tested, well-substantiated, unifying explanation for a set of verified, proven factors.

Explanation:

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