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explanation:
<span>3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles</span>
Answer:
![V_{HCl}=5.05x10^{-3}L](https://tex.z-dn.net/?f=V_%7BHCl%7D%3D5.05x10%5E%7B-3%7DL)
Explanation:
Hello,
In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:
![2*n_{HCl}=n_{Ba(OH)_2}](https://tex.z-dn.net/?f=2%2An_%7BHCl%7D%3Dn_%7BBa%28OH%29_2%7D)
In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:
![2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L](https://tex.z-dn.net/?f=2%2AM_%7BHCl%7DV_%7BHCl%7D%3DM_%7BBa%28OH%29_2%7DV_%7BBa%28OH%29_2%7D%5C%5C%5C%5CV_%7BHCl%7D%3D%5Cfrac%7BM_%7BBa%28OH%29_2%7DV_%7BBa%28OH%29_2%7D%7D%7B2M_%7BHCl%7D%7D%20%3D%5Cfrac%7B0.101M%2A0.050L%7D%7B2%2A0.50M%7D%20%5C%5C%5C%5CV_%7BHCl%7D%3D5.05x10%5E%7B-3%7DL)
Besr regards.
CS2 + 3O2 = CO2 + 2SO2
1 mole of CS2 gives 1 mole of CO2
12 + 2(32) = 76g of CS2 yields 44 g of CO2
Theoretically 1 g of CS2 yields 44/76 g CO2
Therefore 50 g CS2 should yield 50*44 / 76 = 28.95 g
So % yield = 103.6 % ( which is not possible because you can't create matter from nothing).
The 30g cannot be right . This is experimental err.
Answer:
GOOD MORNING DIDI be happy