The anwser is D and I’m sure of it
Area = 16 ft.²
Use the square root process:
√16
√(4 * 4)
2√4 = 4
Answer:
not enough information
Step-by-step explanation:
Dividing altitude by hours, we find the ratios to be 400/2 = 200 ft/h and 700/6 = 116 2/3 ft/h.
These are not the same ratio, so altitude is not proportional to time.
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However, that's not what the question asks. It ask about rate of change. We only have enough information to determine the rate of change between hour 2 and hour 6 is 300 ft in 4 hours, or 75 ft/hour. Since we don't have any other rate of change information, we cannot determine if the rate of change is proportional to anything.
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<em>Comment on the question</em>
We suspect the question is simply worded poorly, and that we're supposed to determine if altitude is proportional to hours. (It is not). If that is actually the question, "rate of change" needs to be left out of the question.
Answer:
No it is still 11 feet from the water at 2 seconds
2.1651 seconds is when it will hit the water
Step-by-step explanation:
h(t) = -16 t^2 +75
This is the formula for the distance
The -16t^2 is due to gravity and the 75 is the height above the bridge
We want to know the height a t =2
h(2) = -16 (2)^2 +75
h(2) =-64 +75
h(2) = 11
The rock will be 11 ft above the water
When will the rock hit the water
h = 0
0 = -16 t^2 +75
Subtract 75 from each side
-75 = -16t^2 +75-75
-75 = -16t^2
Divide by -16
-75/-16 = -16t^2 /-16
75/16 = t^2
Take the square root of each side. We only take the positive square root since time must be positive
sqrt(75/16) =t
5/4 sqrt(3) = t
2.1651 seconds = t
