Answer:
<u>Luteinizing hormone </u>(LH) stimulates Leydig cells to secrete testosterone
<u>Follicle stimulating hormone (FSH)</u> stimulates Sertoli cells to secrete protein and other molecules required for spermatogenesis
Explanation:
Under the influence of gonadotropin-releasing hormone, the anterior pituitary releases luteinizing hormone (LH) and follicle-stimulating hormone (FSH). In males, LH stimulates interstitial cells of testes (Leydig cell) to secrete the hormone testosterone. FSH acts indirectly to stimulate spermatogenesis by causing the release of androgen-binding protein (ABP) from the Sertoli cells. The function of ABP is to maintain the higher concentrations of testosterone to stimulate the final steps of spermatogenesis in the seminiferous tubules.
Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
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The surface area is 1,620
ATP - <span>this is the main energy storage and transfer molecule in the cell.</span>
