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3 years ago

I need to find the volume of this pyramid

Mathematics

1 answer:

luda_lava [24]3 years ago

4 0

The volume is 448 mm^3

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A store received a shipment of 4 boxes of peanuts. All four boxes were stacked on top of each other and measured 12 feet high. H

hram777 [196]

Answer: The store receive 3 ounces of peanuts. <em>(Please tell me if you get the answer correct. ^^)</em>

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3 years ago

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Angelica painted 1/20 of her bedroom walls in 1/2 an hour. How long will it take Angelica to paint her whole bedroom?

julsineya [31]

Angelica would have painted the bedroom in 20 hours if every hour she painted 1/20. But she doesn't paint 1/20 of a room per hour but rather 30 minutes. That means it will take her 10 hours to paint the whole room.

Hope this helps.

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3 years ago

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“encontrar la integral indefinida y verificar el resultado mediante derivación”

Oliga [24]

$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

$I=\displaystyle\int\frac{x^2}{(1+x^3)^2}\,\mathrm dx$

Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

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3 years ago

On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. Point A is at (negative 3, 2).

torisob [31]

Answer:A,C,E

Step-by-step explanation:

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3 years ago

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Help please!!!

KatRina [158]

Corresponding angle

6 0

3 years ago