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mart [117]
3 years ago
5

Problem 7:esvoe71017425b601f756a59bc7b76d2f39502730941492c25f1dd66c7ed01e4bb38ceovse 0N86-C1-52-40-A837-22820 If object A is twi

ce the mass of object B what can be said about their kinetic energies just as they hit the ground
Physics
1 answer:
Natalka [10]3 years ago
7 0

Answer:

the kinetic energy of A will be twice that of B

Explanation:

The formula for calculating kinetic energy is expressed using the formula

KE = 1/2mv²

m is the mass of the object

v is the velocity

For object A:

KEA = 1/2mAvA²

For object B:

KEB = 1/2mBvB² ... 1

If object A is twice the mass of object B, then mA = 2mB

From 1:

KEA = 1/2mAvA²

Substitute mA = 2mB

KEA = 1/2(2mB)vA² .... 2

Divide 1 by 2

KEB/KEA = 1/2mBvB²/mBvA²

KEB/KEA = 1/2vB²/vA²

Assuming they have the same velocities then vA ,= VB

The equation becomes:

KEB/KEA = 1/2vB²/vA²

KEB/KEA = 1/2vB²/vB²

KEB/KEA = 1/2

KEA = 2EB

Hence the kinetic energy of A will be twice that of B

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Answer:

d = 0.38 m

Explanation:

As we know that the person due to the airbag action, comes to a complete stop, in 36 msec or less, and during this time, is decelerated at a constant rate of 60 g, we can find the initial velocity (when airbag starts to work), as follows:

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v₀ = a*t = 60*9.8 m/s²*36*10⁻³s = 21.2 m/s

With the values of v₀, a and t, we can find Δx, applying any kinematic equation that relates all of some of these parameters with the displacement.

Just for simplicity, we can use the following equation:

vf^{2} -vo^{2} = 2*a*d

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Solving for  d:

d = \frac{-vo^{2}}{2*a} = \frac{(21.2m/s)^{2} }{2*588 m/s2} =0.38 m

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3 years ago
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miskamm [114]

Answer:

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In this experiment, you will use a natural indicator to indirectly determine the H+ concentration of some common household solut
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Some of the scientific questions that may be answered through the experiment are:

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To solve this problem we will apply the concept related to the electric field.  The magnitude of each electric force with which a pair of determined charges at rest interacts has a relationship directly proportional to the product of the magnitude of both, but inversely proportional to the square of the segment that exists between them. Mathematically can be expressed as,

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