1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga nikolaevna [1]
3 years ago
10

During an auto accident, the vehicle’s air bags deploy and slow down the passengers more gently than if they had hit the windshi

eld or steering wheel. According to safety standards, air bags produce a maximum acceleration of 60 g that lasts for only 36 ms (or less). How far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60 g?
Physics
2 answers:
Phantasy [73]3 years ago
8 0

Answer:

A person travels 39 cm in coming to a complete stop in 36 ms at a constant acceleration of 60 g.

Explanation:

Hi there!

The equation of position of an object moving in a straight line at constant acceleration is the following:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position at time t.

x0 = initial position.

v0 = initial velocity.

a = acceleration.

t = time.

So, let's see how much distance the person moves inside the car. Let's imagine that the person is initially at rest and suddenly is accelerated at 60 g (60 · 10 m/s² = 600 m/s²). In this case, x0 and v0 = 0 and the traveled distance will be:

x = 1/2 · 600 m/s² · (0.036)²

x = 0.39 m or 39 cm

Here, we have calculated the distance traveled by a person accelerated at 60 g from rest in 36 ms. Notice that the distance is the same if we calculate the traveled distance of a person that is brought to rest in 36 ms with an acceleration of 60 g.

A person travels 39 cm in coming to a complete stop in 36 ms at a constant acceleration of 60 g.

Allushta [10]3 years ago
5 0

Answer:

d = 0.38 m

Explanation:

As we know that the person due to the airbag action, comes to a complete stop, in 36 msec or less, and during this time, is decelerated at a constant rate of 60 g, we can find the initial velocity (when airbag starts to work), as follows:

vf = v₀ -a*t  

If vf = 0, we can solve for v₀:

v₀ = a*t = 60*9.8 m/s²*36*10⁻³s = 21.2 m/s

With the values of v₀, a and t, we can find Δx, applying any kinematic equation that relates all of some of these parameters with the displacement.

Just for simplicity, we can use the following equation:

vf^{2} -vo^{2} = 2*a*d

where vf=0, v₀ =21.2 m/s and a= -588 m/s².

Solving for  d:

d = \frac{-vo^{2}}{2*a} = \frac{(21.2m/s)^{2} }{2*588 m/s2} =0.38 m

⇒ d = 0.38 m

You might be interested in
What is displacement?​
ycow [4]

Answer:

Change in position of an object A vector quantity with unit of distance.

Explanation:

Where is the object going? Final - initial

5 0
3 years ago
Acceleration of 1.5 ms expressed in km /hr2? ​
V125BC [204]
You’re answer is 5 because !! :)
8 0
3 years ago
A boat has a mass of 7660 kg. Its engines generate a drive force of 4080 N due west, while the wind exerts a force of 680 N due
makvit [3.9K]

Answer:

0.29 m/s due west.

Explanation:

According to newton's second law,

Net force acting on an object = mass×acceleration

From the question,

F+F₁+F₂ = ma................ Equation 1

Where F = The force generated from the engine, F₁ = Force exerted by the wind, F₂ = Force exerted due to the water, m = mass of the boat, a = acceleration of the boat.

Given: F = 4080 N , F₁ = -680 N(east), F₂ = -1160 N(east). m = 7660 kg

substitute into equation 1

4080-680-1160 = 7660(a)

2240 = 7660a

Therefore,

a = 2440/7660

a = 0.29 m/s due west.

8 0
2 years ago
A spaceship whose rest length is 350m has a speed of .82c
igomit [66]

Answer:

t'=1.1897*10^{-6} s

t'=1.1897 μs

Explanation:

First we will calculate the velocity of micrometeorite relative to spaceship.

Formula:

u=\frac{u'+v}{1+\frac{u'*v}{c^{2}}}

where:

v is the velocity of spaceship relative to certain frame of reference =  -0.82c (Negative sign is due to antiparallel track).

u is the velocity of micrometeorite relative to same frame of reference as spaceship = .82c (Negative sign is due to antiparallel track)

u' is the relative velocity of micrometeorite with respect to spaceship.

In order to find u' , we can rewrite the above expression as:

u'=\frac{v-u}{\frac{u*v}{c^{2} }-1 }

u'=\frac{-0.82c-0.82c}{\frac{0.82c*(-0.82c)}{c^{2} }-1 }

u'=0.9806c

Time for micrometeorite to pass spaceship can be calculated as:

t'=\frac{length}{Relatie seed (u')}

t'=\frac{350}{0.9806c}     (c = 3*10^8 m/s)

t'=\frac{350}{0.9806* 3.0*10^{8} }

t'=1.1897*10^{-6} s

t'=1.1897 μs

4 0
3 years ago
WILL MARK BRAINLIST. HELP ASAP
Pachacha [2.7K]

Answer:

Less than the distance

3 0
3 years ago
Other questions:
  • Hows does the world spin and we cant feel it
    15·2 answers
  • Which is more work, pushing with 115 N over 15m or lifting 20N over 10 m?
    14·2 answers
  • A battery with e.m.f 12v and the internal resistance 0.5ohms is connected to an electric bulb of resistance 2 ohms. Calculate th
    5·1 answer
  • Find a unit vector normal to the plane containing Bold u equals 2 Bold i minus Bold j minus 3 Bold k and Bold v equals negative
    5·1 answer
  • 1. Using the data from M7:<br>Which four countries are the worst in releasing CO2?​
    15·1 answer
  • The tension in a string is 15 N, and its linear density is 0.85 kg/m. A wave on the string travels toward the -x direction; it h
    15·1 answer
  • Calculate the average speed of a gazelle that runs 140 meters in 5.0 seconds.
    14·2 answers
  • Magnetic and electric fields lab report guide
    5·2 answers
  • Техническое задание
    14·1 answer
  • This graph shows the energy of a reaction over time. Which statement is
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!