Answer:
Distance, d = 0.1 m
It is given that,
Initial velocity of meson,
Finally, the meson is coming to rest v = 0
Acceleration of the meson, (opposite to initial velocity)
Using third equation of motion as :
s is the distance the meson travelled before coming to rest.
So,
s = 0.1 m
The meson will cover the distance of 0.1 m before coming to rest. Hence, this is the required solution.
1 newton / square metre =0.0001 newton / square centimetre
Formula = divide the pressure value by 10000
Answer:
346.70015 m/s
Explanation:
In the x axis speed is
In the y axis
The resultant velocity is given by
The magnitude of the overall velocity of the hamper at the instant it strikes the surface of the ocean is 346.70015 m/s
B is the answer that I know of.