The solution to the system of equations is x = 8, y = 4.
<h3>
How to write the system of equations?</h3>
First, let's define our variables as x and y.
"the sum of two numbers is twelve" is written as:
x + y = 12
"two times the first number minus three times the second number is four" is written as:
2x - 3y = 4
Then the system of equations is:
x + y = 12
2x - 3y = 4
<h3>How to solve it?</h3>
First, we isolate one of the variables in one equation, I will isolate x on the first one to get:
x = 12 - y
Now we replace this on the other equation, so we get:
2*(12 - y) - 3y = 4
Now we can solve this for y.
24 - 2y - 3y = 4
24 - 5y = 4
24 - 4 = 5y
20/5 = y = 4
Now we know the value of y, and:
x = 12 - y = 12 - 4 = 8
Then the solution of the system is:
x = 8, y = 4.
If you want to learn more about systems of equations, you can read:
brainly.com/question/13729904
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Make 8 out of 50:
=8÷50=0.16
Divide:100÷0.16=625.
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. Hoped I helped. :)